All categories

3 years ago

3(x+1)+ 5=2x- 2 i need help with this equation

Mathematics

2 answers:

aev [14]3 years ago

6 0

Answer:

x = -10

Step-by-step explanation:

3(x+1) +5 = 2x -2

Distribute the 3 to the x+1

3x+3 +5 = 2x -2

Combine like terms

3x + 8 = 2x -2

Subtract 2x from both sides

x + 8 = -2

Subtract 8 from both sides

x = -10

Hope this helps!

kumpel [21]3 years ago

4 0

Answer:

x=-10

Step-by-step explanation:

3(x+1)+ 5=2x- 2

Distribute the 3

3(x+1)+ 5=2x- 2 would equal

3x+3+5=2x-2

Combine like terms

3x+3+5=2x-2

3+5=8 So,

3x+8=2x-2

You want to get the numbers with x on one side

Subtract 8 on both sides to get 3x by itself

3x+8-8=2x-2-8

3x=2x-10

Then you have to get the 2x on the other side because you still want x on the other side so you do -2x on both sides

Which gives you

x=-10

That is your answer

You might be interested in

What is the speed of a wave if the wavelength is 100 m and the period is 20 s?

Tom [10]

Answer:

80 m/s

Step-by-step explanation:

3 0

2 years ago

The sum of two consecutive integers is -239 find the two integers

xenn [34]

Answer:

The two consecutive integers are -119 and -120

Step-by-step explanation:

As we know that these two integers are consecutive, that means that they will have a difference of 1. This means that we can find the two integers by adding 1 to the sum of -239 and then dividing it by two

$1-239=-238\\\frac{-238}{2} =-119\\-119-1=-120$

5 0

3 years ago

Please help me out with this question thank you ❤️

devlian [24]

Answer:

log

→

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

PLEASE HURRY , 30 PTS !!!!

Keith_Richards [23]

a = v^2 / r

v^2 = ar

v = √ar

8 0

3 years ago

Read 2 more answers

3(x+1)+ 5=2x- 2 i need help with this equation​

3(x+1)+ 5=2x- 2 i need help with this equation