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Olenka [21]
3 years ago
6

69 points!!!

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:

C)  The solution for the given system of equations are A(0,-5) and B(-4,3)

Step-by-step explanation:

The given system of equation are : x^{2}  + y^{2}  = 25\\2x  + y  = -5

from equation 2, we get   y = -5 - 2x .

Put the above value of y in the equation (1).

We get: x^{2}  + y^{2}  = 25  \implies x^{2}  + (-5-2x)^{2}  = 25

By ALGEBRAIC IDENTITY:

(a+b)^{2}   = a^{2}  +  b^{2}  + 2ab\\ (-5-2x)^{2} = (-5)^{2}  +  (-2x)^{2}  + 2(-5)(-2x)

or, x^{2}  + (-5-2x)^{2}  = 25  \implies x^{2} + (25  +  4x^{2}  + 20x)  = 25

or, 5x^{2}  + 20x = 0  \implies x(5x + 20) = 0

⇒ x = 0 or,   x  = -20/5 = -4

So, the possible values for x are: x  = 0 or  x  = -4

If x  = 0, y = -5-2x = -5-2(0) = -5

and if x = -4, y = -5 -2(-4)   = -5 + 8  = 3

Hence, the solution for the given system of equations are A(0,-5) and B(-4,3)

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