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2 years ago

Here is a list of numbers: 12, 13, 19, 16 ,32, 15, 13.

Mathematics

1 answer:

jonny [76]2 years ago

6 0

Look at the attached picture

Hope it will be helpful to you ...

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Nita wants to buy a new keyboard for her computer. She will buy the keyboard when it is on sale for under $50\$50 $50 dollar sig

Lerok [7]

Answer:

$k$

Step-by-step explanation:

We are told that Nita wants to buy a new keyboard for her computer. She will buy the keyboard when it is on sale for under $50.

Let k be the price in dollars at which Nita will buy the keyboard. Nita will buy the keyboard when its price is less than 50. So we can write our inequality as:

$k$

Therefore, our desired inequality will be $k$ .

5 0

3 years ago

Read 2 more answers

Given that √5 = 2.24 and √50= 7.07 , find √500 and √0.5

sineoko [7]

Answer:

see explanation

Step-by-step explanation:

using the rules of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

$\sqrt{\frac{a}{b} }$ ⇔ $\frac{\sqrt{a} }{\sqrt{b} }$

then

$\sqrt{500}$

= $\sqrt{100(5)}$

= $\sqrt{100}$ × $\sqrt{5}$

= 10 × 2.24

= 22.4

-------------------------------

$\sqrt{0.5}$

= $\sqrt{\frac{50}{100} }$

= $\frac{\sqrt{50} }{\sqrt{100} }$

= $\frac{\sqrt{50} }{10}$

= $\frac{7.07}{10}$

= 0.707

3 0

2 years ago

(Apex 2.2.4 math 8)

Gennadij [26K]

Answer: D

Step-by-step explanation: slope = "rise over run" = 1.5/18 = 3/36 = 1/12 for the 1st section to the landing

slope is the change in height, the vertical change, divided by the change in horizontal distance

2nd section has slope 1/18 and covers 9 feet. That means it rises 1/2 foot

slope = 1/18 = (1/2)/9

the door is 2 feet higher than the ground level, 1.5 + .5 = 2 feet change vertically

5 0

2 years ago

Read 2 more answers

find an equation for the line with the given properties Express the equation in slope intercept form.

zubka84 [21]

In slope Intercept for it is ...y=2x+3

4 0

2 years ago

Find the distance from P to l.

ki77a [65]

$Equation\ of\ a\ line\ from\ 2\ points (x_1;\ y_1);\ (x_2;\ y_2):\\\\y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\(-4;\ 2)\ and\ (3;-5)\\subtitute:\\\\y-2=\dfrac{-5-2}{3-(-4)}\cdot(x-(-4))\\\\y-2=\dfrac{-7}{7}\cdot(x+4)\\\\y-2=-(x+4)\\\\y-2=-x-4\ \ \ |add\ x\ and\ 4\ to\ both\ sides\\\\x+y+2=0\\-------------------\\$

$Point-line\ distance\\l:Ax+By+C=0;\ (x_0;\ y_0)\\\\d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\\\\x+y+2=0\to A=1;\ B=1;\ C=2\\(1;\ 2)\to x_0=1;\ y_0=2\\subtitute\\\\d=\dfrac{|1\cdot1+1\cdot2+2|}{\sqrt{1^2+1^2}}=\dfrac{|1+2+2|}{\sqrt2}=\dfrac{|5|}{\sqrt2}=\dfrac{5}{\sqrt2}=\dfrac{5\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\=\boxed{\dfrac{5\sqrt2}{2}}$

4 0

3 years ago