The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
N = {13, 15, 17, 19}
Step-by-step explanation:
The natural numbers greater than 11 and less than 21 are:
12, 13, 14, 15, 16, 17, 18, 19 and 20
Odd numbers are numbers that have remainders when divided by 2. Out of the numbers above, the numbers with remainders when divided by 2 are 13, 15, 17 and 19.
Since N is the set of odd natural numbers greater than 11 and less than 21,
N = {13, 15, 17, 19}
Answer:
The range is from 125 to 133.
Step-by-step explanation:
That's the lowest and highest the weights go, therefore the range is from 125 and anything in between up to 133.
Answer:
365 days you got it you got it
Step-by-step explanation:
Answer:
It is given that a car traveling at 23 mi/h accelerates to 46 mi/h in 5 seconds.
This means that in 5 seconds it's speed continuously increases to reach 46 mi/h from 23 mi/h.
It maintains that speed for 5 seconds and then slows to a stop in 5 seconds.
This means that the speed of the car is constant i.e. 46 mi/h i.e. the graph is a straight horizontal line parallel to the time axis.
And then it decreases to reach 0 mi/h.
