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vitfil [10]
2 years ago
9

Given a polynomial function f(x) = 2x2 – 3x + 5 and an exponential function g(x) = 2x - 5, what key features do f(x) and g(x) ha

ve in common?
A. Both f(x) and g(x) have the same domain of (9,-infinity).
B. Both f(x) and g(x) have the same range of [0,-infinity).
C. Both f(x) and g(x) have the same x-intercept of (2,0).
D. Both f(x) and g(x) increase over the interval of (-4, infinity).
Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
7 0

Both f(x) and g(x) have the same range of [0,-infinity).

<h3>What is a function?</h3>

A function is an expression that shows the relationship between two or more numbers and variables.

Plotting the functions f(x) = 2x² – 3x + 5 and g(x) = 2ˣ - 5:

Both f(x) and g(x) have the same range of [0,-infinity).

Find out more on function at: brainly.com/question/25638609

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15600=x (x+1)(x+2) What is x?
Andrew [12]
The answer is x = 24
4 0
3 years ago
Read 2 more answers
3x -4y = 13 y = -3x-7
Yuki888 [10]

Step-by-step explanation:

3x-4y=13

y=-3x-7

3x-4(-3x-7)=13

3x+12x+28=13

15x=-15

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y= -3x-7 = 3-7= -4

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8 0
3 years ago
A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate
Katyanochek1 [597]

Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

\frac{dV}{dt}=4 \ m^3/s

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is V=\pi r^2 h

                                                 =( \pi \times 2^2\times h)\ m^3

\therefore V= 4\pi h

Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

\Rightarrow 4\pi \frac{dh}{dt}=4

\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}

The rate change of height does not depend on the height.

Therefore the rate change of height is  \frac{1}{\pi} m/s.

4 0
3 years ago
sam is eating a hamburger. He at 20% of the hamburger with his first bite, 20% of what is left in his second bite, and so on, ea
ryzh [129]

The hamburger will weigh 250 g, if there was originally 160g of it remaining after the second bite given that 20% of the hamburger with his first bite, 20% of what is left in his second bite, and so on, eating 20% of what remains with each bite. This can be obtained by assuming the total weight as x and multiplying the percentages.

<h3>How much did the hamburger weigh?</h3>

Let the total weight of the hamburger be x.

  • First it is given that Sam ate 20% of the hamburger.

The first bite will be,

20% of the hamburger = 20% × x

20% of the hamburger = 20/100 × x

20% of the hamburger = 20x/100

⇒ first bite = 20x/100

Therefore the remaining hamburger will be,

remaining hamburger = x - 20x/100

remaining hamburger = (100x - 20x)/100

⇒ remaining hamburger after first bite = 80x/100

  • Next it is given that Sam ate 20% of the remaining hamburger.

The second bite will be,

20% of the remaining hamburger = 20% × 80x/100

20% of the remaining hamburger = 20/100 × 80x/100

20% of the remaining hamburger = 16x/100

⇒ second bite = 16x/100

Therefore the remaining hamburger will be,

remaining hamburger = 80x/100 - 16x/100

remaining hamburger after second bite = 64x/100

  • It is given that there was originally 160g of it remaining after the second bite.

Then, 64x/100 = 160

x = 160 × 100/64

x = 250 g

Hence the hamburger will weigh 250 g, if there was originally 160g of it remaining after the second bite given that 20% of the hamburger with his first bite, 20% of what is left in his second bite, and so on, eating 20% of what remains with each bite.

Learn more about percentages here:

brainly.com/question/25395

#SPJ4

5 0
1 year ago
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