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Elina [12.6K]
3 years ago
10

Find the area of a regular hexagon with radius length 4 m.

Mathematics
1 answer:
ivann1987 [24]3 years ago
6 0

Answer:

Step-by-step explanation:

24√3

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Write an equation of a line parallel to line EF below in slope-intercept form that passes through the point (2, 6).
N76 [4]

Answer:

y = -⅔x + ²²/₃  

Step-by-step explanation:

1. Calculate the slope of EF

Assume E is at (-2, 5) and F is at (1, 3).

m₁ = (y₂ - y₁)/(x₂ - x₁) = (3 - 5)/(1 -(-2)) = -⅔

2. Calculate the slope of the parallel line

m₂ = m₁ = -⅔

3. Calculate its y-intercept

y = mx + b

6 =-⅔(2) + b

Simplify

6 = -⁴/₃ + b

Add ⁴/₃ to each side

b = 6 + ⁴/₃ = ¹⁸/₃ + ⁴/₃ = ²²/₃

The y-intercept is at (0,²²/₃).

4. Write the equation for the line

y = -⅔x + ²²/₃

The diagram shows EF in red. The parallel line in black passes through (2, 6) with a y-intercept at (0,²²/₃).

7 0
4 years ago
What is the solution set of x2 + y2 = 26 and x − y = 6
jok3333 [9.3K]
The solution set is (9.5, 3.5). Explanation: 9.5(2)+3.5(2) is the same as 19+7 which equals 26. These same numbers are used for x-y=6, which is 9.5-3.5=6.
8 0
4 years ago
Please help me lollll
WITCHER [35]

Answer:

lolll what

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If you vertically shift the quadratic parent function f(x)=x^2 down nine units what is the equation of the new function
sleet_krkn [62]

Answer:

{x}^{2}  - 9

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!
Dimas [21]

Step-by-step explanation:

5x^2+2x=1

5x^2+2x-1=0

x=-b+/-√b^2-4ac÷2a

x=-2+/-√-2^2-(4×5×-1)÷2×5

x=-2+/+√4--20÷10

x=-2+/-√24÷10

x=-2+√24÷10 or -2-√24÷10

x=-2+4.9÷10 or -2-4.9÷10

x=2.9÷10 or -6.9÷10

x=0.29 or -0.69

4 0
4 years ago
Read 2 more answers
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