<em>hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>
Answer:
800n+1050
Step-by-step explanation:
800(n+1)+250 = 800n+800+250 = 800n+1050.
Hope this helps!
Good luck with your test + I hope you do well on it.
Please mark me as brainliest!
Ball hit the ground is when the function equals zero
0=-16t^2+46t+6
we can't factor so use quadraticformula
for
ax^2+bx+c=0
x=

x=

x=

x=

x=

x=

or

x=

or x=

x=-1/6 or x=3
we cannot have negative time because time starts at 0
disregard -1/6 as a possible answer
answer is after 3 seconds
1. Vertex E is the center of the circle, A and B are on the circle.
2. Any angle with these properties (i. E is center, AE and AB are radii) is called a central angle.
3. Check the picture.
4. An important property of these angles is that the measure of the arc AB = m(AEB)
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.