Answer:
Step-by-step explanation:
Required
Which equals 
Collect like terms
Divide both sides by 2
Collect like terms
Divide both sides by 2
Collect like terms
Divide both sides by -2
Divide both sides by 2
Collect like terms
Divide both sides by 2
Collect like terms
Hence, the equations with the required solution are:
Answer:
No, Because students who have the same math grade can be different heights
Step-by-step explanation:
C is the answer DO NOT PICK D
You have the put the correct input and output IN ORDER so D is the wrong answer
X = 1/2 =0.500
Mark as brainliest
Answer:
$77.5
Step-by-step explanation:
7.75*10 = 77.5
Answer:
The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.
Step-by-step explanation:
According to DeMorgan's Theorem:
(W.X + Y.Z)'
(W.X)' . (Y.Z)'
(W'+X') . (Y' + Z')
Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.
For the original function:
(W . X + Y . Z)'
= (1 . 1 + 1 . 0)
= (1 + 0) = 1
For the compliment:
(W' + X') . (Y' + Z')
=(1' + 1') . (1' + 0')
=(0 + 0) . (0 + 1)
=0 . 1 = 0
Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.
Without the parenthesis the compliment equation looks like this:
W' + X' . Y' + Z'
1' + 1' . 1' + 0'
0 + 0 . 0 + 1
Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.
Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.
