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netineya [11]
3 years ago
11

What is the resultant equation of a quadratic function that touches the x-axis at 1, cuts the y- axis at -1 and passes through t

he points (-1,-4) and (2,15)?
No answer needed, take the points.
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

Answer:

2(7+28)3= 180     (not answer)

Step-by-step explanation:

Thanks for them!!

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The graph below shows the height of a tunnel f(x), in feet, depending on the distance from one side of the tunnel x, in feet:
denis23 [38]
Part A) x-intercepts simply show that when the value of the function is zero. Vertex coordinates show that when the function obtains its maximum value. When x=50, function obtains its maximum value and it's 75. The function is increasing in the interval (0, 50) and decreasing in the interval (50, 100). In regard to the height and distance of the tunnel, these numbers show that decreasing and increasing intervals are symmetric. Each number from the intervals has its own pair in the corresponding interval and they are located in the same distance from the midpoint (50,75)

Part B) In order to calculate the average rate of change, we can first write the function. Using the information about the x-intercept and the vertex coordinates, we find that our function is f(x)=-0.03x^{2}+3x.
Plugging 15 and 35 in x, we can find the values of the function, i.e. 
f(15)=38.25 and f(35)=68.25.
Then, the average change is \frac{68.25-38.25}{35-15}=1.5
4 0
3 years ago
Read 2 more answers
HELP PLEASE!!! Find an equation of a line through (√3,12) parallel to the line:
amm1812

Answer:

just put like what oh yea put 72

3 0
3 years ago
What line is parallel to 2x+5y=6 that goes through (5,3)
Anna11 [10]

Answer:

4y = x - 17

Step-by-step explanation:

First off, in the equation given : 2x + 5y = 6 , make y the subject of the formula which will give y = \frac{-2x}{5} + \frac{6}{5}  which make the gradient, m, the coefficient of x = \frac{-2}{5}  . Since the line we're looking for is parallel to the one we were given, their respective gradients would be the same. (If they were perpendicular, the gradient of the new line would be a negative inverse of the given line)

Then you proceed to use the one-point formula : y - y₀ = m(x - x₀), where   y₀ = 3 and x₀ = 5 from the point it goes through (5, 3)

y - 3 = \frac{1}{4}(x - 5); y - 3 = \frac{x}{4} - \frac{5}{4};  y = \frac{x}{4} - \frac{5}{4} +3

y = \frac{x}{4} - \frac{17}{4};  y = \frac{x-17}{4}  ;   4y = x - 17

7 0
2 years ago
A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec
Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (<em>n</em> ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18

The sample size is, <em>n</em> = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191

(a)

The null hypothesis is:

<em>H</em>₀: The usual load is 13 credits, i.e. <em>μ</em> = 13.

Assume that the significance level of the test is, <em>α</em> = 0.05.

Construct a (1 - <em>α</em>) % confidence interval for population mean to check the claim.

The (1 - <em>α</em>) % confidence interval for population mean is given by:

CI=\bar x\pm z_{\alpha/2}\times SE

For 5% level of significance the two tailed critical value of <em>z</em> is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Construct the 95% confidence interval as follows:

CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)

As the null value, <em>μ</em> = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

3 0
2 years ago
Read 2 more answers
What is -3.5 as a fraction
Alex_Xolod [135]
-7/2 (seven halves) .
5 0
3 years ago
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