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3 years ago

Can u solve this problem in show your work

Mathematics

2 answers:

aksik [14]3 years ago

5 0

Hey there!

We can solve this problem by doing PEMDAS, which lists:

$Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction$

We have in this equation

$Parentheses \\ Exponents \\ Dvision$

Let's sp;ve this equation now!

Parentheses ↓

$(6 -3) = 3$

Exponents ↓

$3^2 = 9$

Division ↓

$\frac{36}{9} = 9$

Okay now , I show you the steps so it can be easier to solve!

$\frac{36}{(6-3)^2} \\ \\ 6-3 = 3 \\ \\ \frac{36}{3^2} \\ \\ 3^2 = 9 \\ \\ \frac{36}{9} \\ \\ \\ \\ Answer: 4$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

pshichka [43]3 years ago

3 0

36/(6-3)2

36/3(2) 3 squared (3x3) equals 9

36/9

4

your final answer is four

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$\tan\,\theta =\frac{\sqrt{21} }{2}$

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Step-by-step explanation:

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As both $sin\,\theta$ ,

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$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

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2 years ago

5 2/3 divided by 3/2

Zinaida [17]

Answer: 34/9

Step-by-step explanation:

5 2/3 / 3/2

= 17/3 / 3/2

=17/3 x 2/3 [reciprocal]

=34/9

Hope it helped u,

pls mark as the brainliest

^_^

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