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denis-greek [22]
3 years ago
7

A picture frame has a perimeter of 40 inches. Its length is 2 inches greater than one-half its width. Let w represent the width

of the picture frame, and let l represent the length. Which system of equations can be used to find the dimensions of the picture frame?
Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0
L = 2 + .5W
2L + 2W = 40

SOLVING (if needed)
Substitute 2 + .5w in for l in the second equation and solve for w.
2(2 + .5w) + 2w = 40
4 + w + 2w = 40
Combine like terms and subtract 4 from both sides
3w = 36
Divide both sides by 3
w = 12 in.
l = 2 + .5w
l = 2 + .5(12)
l = 8 in.
vovikov84 [41]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Yes

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Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

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=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

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=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

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