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mina [271]
3 years ago
7

Which statement is true of DNA polymerase?

Biology
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

b) DNA polymerase can synthesize DNA in the 5' to 3' direction

DNA polymerase is only able to synthesize a new strand of DNA and not mRNA. It is only able to do this in the 5' to 3' direction. The leading template strand runs in the 3' to 5' direction and so the new complementary strand is synthesized in a 5' to 3' direction in one continuous run, following the replication fork as it 'unzips' the DNA.

hope it helps btw i did this test and i got it correct

check my screenshot below

please mark me brainliest

Explanation:

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Which organism below has a problem in maintaining cellular electrolyte and fluid balance in its environment? Select one:
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Answer:

C

Explanation:

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2 years ago
Things of the same species have similar morphology and can ____
STALIN [3.7K]
Things of the same species have similar morphology and can INTERBREED
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In the first stage of cellular respiration, two molecules of pyruvate are produced. in the remaining stages, a number of product
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ATP, mitocondria 

the stages are the citric acid cycle and the electron transport chain 
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3 years ago
In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s
lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

<h3>A)</h3>

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp  × 1000 =

0.305  × 0.155 × 1000 = 47 individuals will be double crossover.

<h3>B)</h3>

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

<u>cc = 0.7</u>

Observed DCO / 47 = 0.7

Observed DCO = 0.7  × 47

Observed DCO ≅ 33

<h3>C)</h3>

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

<h3>D)</h3>

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0
3 years ago
Which of the following is not an effect of complement activation? Select one: Interference with viral replication Increased phag
Nostrana [21]

Answer:

The correct answer is "Interference with viral replication".

Explanation:

The complement system is an essential part of the immune system that involves the activation of a series of proteins that act as a cascade and result in the development of inflammatory responses that help to fight infections. There are multiple effects of complement activation, however interference with viral replication is not one of them. The molecules that are able to interfere with viral replication are called interferons, and they synthesis and activation are not related with complement activation.

6 0
3 years ago
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