Answer:
The total volume of the water in the tank after 20 minutes = 1220 gallons
Step-by-step explanation:
Rate of water pumped into the tank r (t) = 30 (1 -
)
Initial volume of water in the tank = 800 gallons
The water in the tank after 20 minutes = Initial volume of water in the tank + Volume of water being pumped in the tank

= 
Where a = 0 , b = 20
Put the value of r (t) in above equation we get
= 
= ![30 [ t + \frac{e^{-0.16t} }{0.16} ]](https://tex.z-dn.net/?f=30%20%5B%20t%20%2B%20%5Cfrac%7Be%5E%7B-0.16t%7D%20%7D%7B0.16%7D%20%5D)
= 
= 420 gallon
Now, total volume in the tank



Therefore the total volume of the water in the tank after 20 minutes = 1220 gallons
square has 4 equal sides
so A = 144 = 12^2
A = L x W
= W. W
= W^2
12^2 = W^2
so W = 12
answer: one side of the square = 12
The total number of packages completed was 41 and with 60 moustraps per package so 41 x 60 = 2460. Of these, 52 traps were from the previous shift and 34 were rejects so 2460-52-34 = 2374 produced + 24 in the last unsealed package = 2374 +24 = 2398.
Answer:
x= −297
/13
Step-by-step explanation: