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4 years ago

Answer this one please

Mathematics

1 answer:

Fittoniya [83]4 years ago

4 0

Answer:

105 cm²

Step-by-step explanation:

We can see that the area at the square at the bottom, since one side is 5, is 5²=25. Then, we know that the height of the triangles is 8, the base is 5, and there are 4 of them, so ((5*8)/2)*4=80. Add these up to get 105 as our total

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Before flipping a fair coin, Sunil assesses that he has a 50% chance of obtaining tails. Subjective probability Empirical probab

ASHA 777 [7]

Answer:

a) Classical

b) Subjective

c) Empirical

Step-by-step explanation:

a) Classical probability: In classical probability, all the events have the same probability. When flipping a coin, the probability of getting tails is the same as the probability of getting tails, therefore, the probability of both events is 50%.

b) Subjective probability: Subjective probability is derived from a personal judgement based on previous experiences. In this case, John would be calculating his probability of receiving A's based on his previous semesters.

c) Empirical probability: is the ratio between the number of outcomes a scenario happens and the total of trials in an ACTUAL EXPERIMENT. In this case, the reporter would be calculating this probability based on his previous experiences attending actual conferences.

5 0

3 years ago

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the v

Svetllana [295]

Answer:

The differential equation becomes -

$\frac{dV}{dt} = k\sqrt[3]{V}$ i.e. $\frac{dV}{dt} = kV^{\frac{1}{3} }$

Step-by-step explanation:

Given - The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

To find - Write a differential equation that describes the relationship.

Proof -

Rate of change of volume V with respect to time t is represented by $\frac{dV}{dt}$

Now,

Given that,

The rate of change of the volume V of water in a tank with respect to time t is directly proportional to the cubed root of the volume.

⇒ $\frac{dV}{dt}$ ∝ $\sqrt[3]{V}$

Now,

We know that, when we have to remove the Proportionality sign , we just put a constant sign.

Let k be any constant.

So,

The differential equation becomes -

$\frac{dV}{dt} = k\sqrt[3]{V}$ i.e. $\frac{dV}{dt} = kV^{\frac{1}{3} }$

6 0

3 years ago

At the city museum, child admission is $5.30 and adult admission is $9.70 . On Wednesday, three times as many adult tickets as c

romanna [79]

24 will be sold on that ray

6 0

4 years ago

Find the 12th term<br> 1,4, 16, 64,<br> ...

IgorC [24]

Step-by-step explanation:

for getting to next term you multiple 4, so it's an exponential sequence

a×r^n-1

1×4^n-1

sequence: 4^n-1

12th term: 4^12-1

=4^11

=4194304

hope it helps!!

5 0

3 years ago

Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a

evablogger [386]

Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1= $\frac{1}{2} *PQ*RM$

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2= $\frac{1}{2} *SR*PN$

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1= $\frac{1}{2}*PQ*h$

S2= $\frac{1}{2}*SR*h$

Adding them together, we get the area of the whole trapezoid:

S=S1+S2= $\frac{1}{2} (PQ+SR)h,$

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> $A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}$