3 years ago

Need help ASAP now plz now z now now now

Mathematics

1 answer:

Viktor [21]3 years ago

6 0

Root root 20^2 - 4^2
X = 2

You might be interested in

Please help!! Express the function graphed on the axes below as a piecewise function.

Anton [14]

I tried to send the picture vertically, but the bottom part was cut off. So I turned it horizontally. Please understand that.

5 0

2 years ago

Which of these triangle pairs can be mapped to each other using a translation and a rotation about a point A? Select one answer

Elenna [48]

The answer is the first and the third figure,attached

5 0

3 years ago

4x-5(x-2)=12x+4-x ??????????????

Anestetic [448]

4x - 5(x - 2) = 12x + 4 - x
4x - 5(x) - 5(-2) = 12 - x + 4
 4x - 5x + 10 = 11x + 4
 -x + 10 = 11x + 4
 + x + x 
 10 = 12x + 4
 - 4 - 4
 6 = 12x
 12 12
 0.5 = x

6 0

3 years ago

Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function

dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

$f(x)=x^3+2x^2-x-2$

The $y-intercept$ occurs when $x=0$ , so:

$f(0)=(0)^3+2(0)^2-(0)-2=-2$

Therefore, the $y-intercept$ is the given by the point:

$\boxed{(0,-2)}$

From the figure we have three $x-intercepts$ :

$\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}$

So, the $x-intercepts$ occur when $y=0$ . Thus, proving this:

$f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0$

7 0

3 years ago

Read 2 more answers

Ardi mempunyai uang Rp500.000,00 ia

miv72 [106K]

Translate to english and i’ll help

5 0

3 years ago