Plug the -4 into equation
f(-4) = 5(-4) -3
multiply 5•-4= -20
then subtract -20-3
when you have two negatives you add
= -23
Answer:
25
Step-by-step explanation:
The number that needs to be added is the square of half the x-coefficient:
(-10/2)^2 = 25
_____
Adding that gives ...
(x -5)^2 = 32
x = 5 ± 4√2
Your formula for this is

and

. Get everything on one side of the equals sign, set it equal to 0 and factor. When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27. The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2