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Fiesta28 [93]
3 years ago
5

What is the first step to solve this equation: 3x =44

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0

You need to divide 3 on both sides

nataly862011 [7]3 years ago
6 0

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Divide by 3 on both sides

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If f(x)= 5x-3 what is f(-4)
Over [174]
Plug the -4 into equation

f(-4) = 5(-4) -3

multiply 5•-4= -20

then subtract -20-3

when you have two negatives you add

= -23
f ( - 4) = 5( - 4) - 3 =  - 23
3 0
3 years ago
Which number should be added to both sides of the equation to complete the square x^2-10x=7
mixer [17]

Answer:

  25

Step-by-step explanation:

The number that needs to be added is the square of half the x-coefficient:

  (-10/2)^2 = 25

_____

Adding that gives ...

  (x -5)^2 = 32

  x = 5 ± 4√2

5 0
3 years ago
Solve for x.<br>A. x =9<br>B. x = 3<br>C. x = 4<br>D. x = 27
meriva
Your formula for this is 9^{2} =x(24+x) and 81=24x+ x^{2}.  Get everything on one side of the equals sign, set it equal to 0 and factor.  When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27.  The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.
8 0
3 years ago
Bernie bought a pair of shoes at the store when they were having a 30% off sale. If the
Ne4ueva [31]
It’s $12.60 dollars!!!
3 0
2 years ago
In circle E, AC=4, CG=6, and AH=3, Find HB and EG. If necessary, round to the tenths place.
bezimeni [28]
Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2




3 0
3 years ago
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