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Fiesta28 [93]
3 years ago
5

What is the first step to solve this equation: 3x =44

Mathematics
2 answers:
alisha [4.7K]3 years ago
7 0

You need to divide 3 on both sides

nataly862011 [7]3 years ago
6 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

Divide by 3 on both sides

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Please help me I don’t understand it well
Makovka662 [10]

Answer

C

Step-by-step explanation:

I thing so because if 2x+7 least then the other equation. Then the line will show that it is greater

7 0
3 years ago
Please help me I am horrid at math!
Serga [27]

Answer:23 inches

<h2>Step-by-step explanation:all sides equal 23 when added together</h2>
7 0
2 years ago
What is blank/11 = 12/44 equivalent fractions
nordsb [41]

Answer:

3/11

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
A city had population 67,255 on january 1, 2000, and its population has been increasing by 2935 people each year since then. A l
irina1246 [14]

We are given: On january 1, 2000 initial population   = 67,255.

Number of people increase each year = 2935 people.

Therefore, 67,255 would be fix value and 2935 is the rate at which population increase.

Let us assume there would be t number of years after year 2000 and population P after t years is taken by function P(t).

So, we can setup an equation as

Total population after t years = Number of t years * rate of increase of population + fix given population.

In terms of function it can be written as

P(t) = t * 2935 + 67255.

Therefore, final function would be

P(t) = 2935t +67255.

So, the correct option is d.P(t) = 67255 + 2935t.

4 0
3 years ago
Read 2 more answers
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