9514 1404 393
Answer:
(8.49; 225°)
Step-by-step explanation:
The angle is a 3rd-quadrant angle. The reference angle will be ...
arctan(-6/-6) = 45°
In the 3rd quadrant, the angle is 45° +180° = 225°.
The magnitude of the vector to the point is its distance from the origin:
√((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49
The polar coordinates can be written as (8.49; 225°).
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<em>Additional comment</em>
My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.
Answer:
the answer is the choice C. because
27/9 equals 3 . the answer is 3 .
The general solutions always have some additive/multiplicative constant, that you must fix in the particular solution.
In order to do so, you need to impose that the particular solution passes through a certain point. In your case, you have
and you want
Put everything together, and you have
Since the cosine is zero in the chosen point. So, we've fixed the value of the constant, and the particular solution is found:
Answer:
Step-by-step explanation:
9x9+6x8-6x+6=93
4x2+3x5-4x+3=11
93-11=82
Answer:
y = -8
Step-by-step explanation:
If the equation is parallel to y = 9, the you already know that the equation must be y = some value. It passes through the point (3,-8). Just put that y value into the equation to get y = -8
