Answer:
x = -16
Step-by-step explanation:

Given:
The first two terms in an arithmetic progression are -2 and 5.
The last term in the progression is the only number in the progression that is greater than 200.
To find:
The sum of all the terms in the progression.
Solution:
We have,
First term : 
Common difference : 


nth term of an A.P. is

where, a is first term and d is common difference.

According to the equation,
.



Divide both sides by 7.

Add 1 on both sides.

So, least possible integer value is 30. It means, A.P. has 30 term.
Sum of n terms of an A.P. is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Substituting n=30, a=-2 and d=7, we get
![S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D%5Cdfrac%7B30%7D%7B2%7D%5B2%28-2%29%2B%2830-1%297%5D)
![S_{30}=15[-4+(29)7]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B%2829%297%5D)
![S_{30}=15[-4+203]](https://tex.z-dn.net/?f=S_%7B30%7D%3D15%5B-4%2B203%5D)


Therefore, the sum of all the terms in the progression is 2985.
Answer:
y = 2x
y = 3x - 3
Step-by-step explanation:
Hi,
<u>y = 2x</u>
<u>6 = 2(3)</u>
<u>6 = 6</u>
<u>That's a solution</u>
<u>y = 3x - 3</u>
<u>6 = 3(3) - 3</u>
<u>6 = 9 - 3</u>
<u>6 = 6</u>
<u>That's a solution</u>
Hope this helps :)

In case there is no double entry system is followed, profit can be calculated by comparing the opening and closing capital. In the given situation this can be calculated as:
Opening Capital Rs.200000
Add: Capital Introduced Rs.200000
Add: Profit for the year Rs. 250000
Less: Loss for the year Rs.NIL
Less: Drawings Rs. 30000
--------------------
Capital at the end of the year Rs.620000
-------------------
Loan taken is a liability and loan given is asset, that will not affect the capital.
<h2>ƑƠԼԼƠƜ MЄ❤</h2>