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Marina86 [1]
3 years ago
12

A moving walkway has a speed of 0.5 m/s to the east. A stationary observer

Physics
1 answer:
ch4aika [34]3 years ago
6 0

Answer: 0.3 m/sec

Explanation:

Vrel = (Vs-Vm) = (0.8-0.5) = 0.3 m/sec

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When using a stream table in a classroom setting what are three factors that can be controlled?
UNO [17]

Answer:

<h3><em>These include the slope of the land, the nature of the land surface, the placement of dams, and the direction of topsoil disturbance as created by farming activities. Materials: Students should work in groups of 3 or 4, or as materials allow.</em></h3>

Explanation:

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3 0
2 years ago
An electron is travelling in a straight line with a kinetic energy K = 1.60 x 10^-17J. What are (a) the magnitude and (b) the di
faust18 [17]

Answer:

(a) 1000 N/C

Explanation:

Kinetic energy of electron, K = 1.6 x 10^-17 J

distance, d = 10 cm = 0.1 m

Let the potential difference is V and the electric field is E.

(a) The relation between the kinetic energy and the potential difference is

K = e V

V = K / e

Where, e be the electronic charge = 1.6 x 10^-19 C

V = \frac{1.6\times 10^{-17}}{1.6\times 10^{-19}}

V = 100 V

The relation between the electric field and the potential difference is given by

V = E x d

100 = E x 0.1

E = 1000 N/C

(b) The force acting on the electron, F = q E

where q be the charge on electron

So, F = -e x E

It means the direction of electric field and the force are both opposite to each other.

The direction of electric field and the force on electron is shown in the diagram.

5 0
4 years ago
What is the formula of initial velocity​
inysia [295]
Initial Velocity formulas are used to find the initial velocity of the moving body if some of the terms are given. Initial velocity can be formulated in a unit of a meter per second i.e. ms^{-1}. ms−1.
7 0
3 years ago
Read 2 more answers
In an elastic collision, a 580 kg bumper car collides directly from behind with a second, identical bumper car that is traveling
kozerog [31]

Answer:  vl = 2.75 m/s vt = 1.5 m/s

Explanation:

If we assume that no external forces act during the collision, total momentum must be conserved.

If both cars are identical and also the drivers have the same mass, we can write the following:

m (vi1 + vi2) = m (vf1 + vf2) (1)

The sum of the initial speeds must be equal to the sum of the final ones.

If we are told that kinetic energy must be conserved also, simplifying, we can write:

vi1² + vi2² = vf1² + vf2² (2)

The only condition that satisfies  (1) and (2) simultaneously is the one in which both masses exchange speeds, so we can write:

vf1 = vi2 and vf2 = vi1

If we call v1 to the speed of the leading car, and v2 to the trailing one, we can finally put the following:

vf1 = 2.75 m/s  vf2 = 1.5 m/s

8 0
3 years ago
When a body is accelerated under water, some of the surrounding water is also accelerated. This makes the body appear to have a
Alenkinab [10]

Solution :

Mass of the sphere, m = 10 kg

Diameter, D = 300 mm = 0.3 m

Volume of the sphere is $V=\frac{4}{3} \pi \left(\frac{0.3}{2}\right)^3$

                                       $V=0.01414 \ m^3$

So the volume of displaced water, $V_w=V = 0.01414 \ m^3$

Additional mass, $m_w = \frac{1}{2} \ \rho_w\times v_w$

                                  $=\frac{1}{2} \times 1000 \times 0.01414$

                                  $=7.0686 \ kg$

So the total mass, $M = m_w+m$

                                   = 7.0686 + 10

                                   = 17.0686

Force required, F = Ma

$F=17.0686 \times 10$

   = 170.686 N

4 0
3 years ago
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