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Naddika [18.5K]
3 years ago
5

An electron is travelling in a straight line with a kinetic energy K = 1.60 x 10^-17J. What are (a) the magnitude and (b) the di

rection of the electric field that will stop the electron in a distance of 10.0 cm? For part (b), make a drawing showing the direction of motion of the electron, the direction of the electric field and the electric force on the electron

Physics
1 answer:
faust18 [17]3 years ago
5 0

Answer:

(a) 1000 N/C

Explanation:

Kinetic energy of electron, K = 1.6 x 10^-17 J

distance, d = 10 cm = 0.1 m

Let the potential difference is V and the electric field is E.

(a) The relation between the kinetic energy and the potential difference is

K = e V

V = K / e

Where, e be the electronic charge = 1.6 x 10^-19 C

V = \frac{1.6\times 10^{-17}}{1.6\times 10^{-19}}

V = 100 V

The relation between the electric field and the potential difference is given by

V = E x d

100 = E x 0.1

E = 1000 N/C

(b) The force acting on the electron, F = q E

where q be the charge on electron

So, F = -e x E

It means the direction of electric field and the force are both opposite to each other.

The direction of electric field and the force on electron is shown in the diagram.

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We can understand better this situation using a diagram with the forces acting on it.

In the attached image we can see that when the gravity center is bouncing outside from the area of the pedestal, the object will be out of balance and will fall.

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3 years ago
David rowed a boat upstream for three miles and then returned to point he started from. The entire journey took four hours. The
frez [133]
Upstream speed = S - 1
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3 years ago
The current in a lamp is 0.5 ampere when it is plugged into a standard wall outlet. What is the resistance of the lamp when it i
lidiya [134]

The resistance of the lamp plugged in to a standard wall outlet with a current of 0.5 amps is 240 Ω (ohms)

Explanation:

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The current in the lamp is 0.5 ampere

Resistance (R) = V/ I

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1st B is correct option

2nd D is correct option

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