A man who has male pattern baldness (X^bY) marries a woman who does not carry the allele (X^BX^B). What genotypic ratios would b
e expected of their children?
1 answer:
Answer:
2
:2
Explanation:
<em>The genotypic ratio of expected of their offspring would be 2</em>
<em>:2</em>
<em>.</em>
From the illustration, the genotype of the man with male pattern baldness is
while the genotype of the woman without the baldness allele is
.
Crossing the two genotypes in marriage:
x 
Progeny:

<em>Hence, the genotypic ratio of the offspring becomes:</em>
2
:2
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