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My name is Ann [436]
3 years ago
13

A man who has male pattern baldness (X^bY) marries a woman who does not carry the allele (X^BX^B). What genotypic ratios would b

e expected of their children?
Biology
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

2X^BX^b:2X^BY

Explanation:

<em>The genotypic ratio of expected of their offspring would be 2</em>X^BX^b<em>:2</em>X^BY<em>.</em>

From the illustration, the genotype of the man with male pattern baldness is X^bY while the genotype of the woman without the baldness allele is X^BX^B.

Crossing the two genotypes in marriage:

                           X^bY   x   X^BX^B

Progeny: X^BX^b    X^BX^b    X^BY       X^BY

<em>Hence, the genotypic ratio of the offspring becomes:</em>

2X^BX^b:2X^BY

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