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Dovator [93]
3 years ago
6

Move vertex B to a different location. What is the sum of the angle measures of the quadrilateral?

Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

360 degrees

Step-by-step explanation:

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Rebecca has 45 coins, all nickels and dimes. The total value of the coins is $3.60. How many
kvv77 [185]

Answer:

Rebecca has 18 nickels and 27 dimes

Step-by-step explanation:

Let x be the number of nickels Rebecca has, then 45-x is the number of dimes she has.

The total value of Rebecca's coins is $3.60.

1 nickel - 5 cents

x nickels - 5x cents

1 dime - 10 cents

45-x dimes - 10(45-x) cents

Total x nickels and 45-x dimes is 5x+10(45-x) cents that is $3.60=360 cents. So,

5x+10(45-x)=360

5x+450-10x=360

5x-10x=360-450

-5x=-90

5x=90

x=18

45-x=45-18=27

4 0
3 years ago
Suppose the polynomial function below represents the power generated by a wind turbine, where x represents the wind speed in met
Elis [28]

Answer:

<em>f(10) or the power generated by the wind turbine at the wind speed of 10 m/s is </em><em>190.26 kW</em>

Step-by-step explanation:

The given polynomial function is,

f(x) = 0.08x^3 + x^2 + x + 0.26

where,

x represents the wind speed in meters per second,

y represents the kilowatts generated.

Putting x=10, we can get the value of f(10).

So,

=f(10)

= 0.08(10)^3 + (10)^2 + (10) + 0.26

= 0.08(1000) + (100) + (10) + 0.26

= 80 + 100 + 10 + 0.26

=190.26

Therefore,at x=10 or when the wind speed is 10 m/s, then y or the power generated by the wind turbine will be 190.26 kW

6 0
3 years ago
Read 2 more answers
Help me!! I need help fast.
Elden [556K]

Hot air rises and cold air sinks

7 0
3 years ago
Read 2 more answers
Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

So f(0,0)=ln19.

8 0
3 years ago
Help me with answers plz
pav-90 [236]
3÷8+1÷8-(9÷8+5÷8) =3÷8+1÷8-(14÷8) =3÷8+1÷8-14÷8 =(3+1-14)÷8 =-10÷8 =-5÷4 =-1.25
3 0
3 years ago
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