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Ostrovityanka [42]
3 years ago
9

HELP FAST WILL GIVE BRAINLIEST

Mathematics
1 answer:
katovenus [111]3 years ago
8 0

Answer:The square roots of 13 is 3.6, The square root of 85 is 9.2

Step-by-step explanation:

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Suppose the FAA weighed a random sample of 20 airline passengers during the summer and found their weights to have a sample mean
Orlov [11]

Answer:

Step-by-step explanation:

Given Parameters

Mean, x = 180

total samples, n = 20

Standard dev, \sigma = 30

\alpha = 1 - 0.95 = 0.05 at 95% confidence level

Df = n - 1 = 20 - 1 = 19

Critical Value, t_\alpha, is given by

t_{c}=t_{\alpha, df} = t_{0.05,19} = 1.729

a).

Confidence Interval, \mu, is given by the formula

\mu = x +/- t_c \times \frac{s}{\sqrt{n} }

\mu = 180 +/- 1.729 \times \frac{30}{\sqrt{20} }

\mu = 180 +/-11.5985

191.5985 > \mu > 168.4015

b).

Critical Value, t_{\alpha/2}, is given by

t_{c}=t_{\alpha/2, df} = t_{0.05/2,19} = 2.093

Confidence Interval, \mu, is given by

\mu = x +/- t_c \times \frac{s}{\sqrt{n} }

\mu = 180 +/- 2.093 \times \frac{30}{\sqrt{20} }

    = 180 +/- 14.0403

    = 165.9597 < \mu < 194.0403

8 0
3 years ago
To increase an amount by 30%, what single multiplier would you use? and To decrease an amount by 30%, what single multiplier wou
Kamila [148]

Answer:

To increase, use 1.3

to decrease, use .7

Step-by-step explanation

6 0
3 years ago
Perform the indicated operation. Be sure the answer is reduced.<br> x+1/x-8 - x/8-x =
Dominik [7]

Answer:

the second option

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
C=4.62 a =2.2 what is c
DaniilM [7]

Answer: if your question was C-A then it would be 2.42

Step-by-step explanation:

4.62-2.2

7 0
3 years ago
PLEASE HELP ME! I really need help y'all...
ikadub [295]

just a quick clarification, tis usually -4.9 and that's a rounded number to reflect earth's gravity on an object in motion, but -5 is close enough :)

\bf ~~~~~~\textit{initial velocity in meters} \\\\ h(t) = -4.9t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf h(x)=-5(\stackrel{\mathbb{F~O~I~L}}{x^2-8x+16})+180\implies h(x)=-5x^2+40x-80+180 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x)=-5x^2+\stackrel{\stackrel{v_o}{\downarrow }}{40} x+\stackrel{\stackrel{h_o}{\downarrow }}{\boxed{100}}~\hfill

8 0
4 years ago
Read 2 more answers
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