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Lynna [10]
3 years ago
9

I forgot what to do

Mathematics
1 answer:
kvv77 [185]3 years ago
8 0
Pretty sure it would be 21x^2+16x+17y
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The Art and History Museum offers a family discount card for a donation of $57. I The table shows the price per person with and
Murljashka [212]

Answer:

8 number of visits will be the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

Step-by-step explanation:

                             Price without Discount Card   Price with Discount Card

Ticket (12 & Under)        $10                                             $8

Adult's Ticket                  $15                                           $12

Let x be the number of visits

Price without discount card for 2 adults and 1 child ticket

Price without discount for x visits = x(15 \times 2+ 10)=40x

Price with discount for x visits =57+ x(12 \times 2+ 8)=57+32x

Now to find For what number of visits will the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

57+32x< 40x

57<8x

7.1<x

So, 8 number of visits will be the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

8 0
3 years ago
If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)
Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

\log_dabc=\log_da+\log_db+\log_dc

Then using the change of base formula, we can derive the relationship

\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}

This immediately tells us that

\log_dc=\dfrac1{\log_cd}=\dfrac12

Notice that none of a,b,c,d can be equal to 1. This is because

\log_1x=y\implies1^{\log_1x}=1^y\implies x=1

for any choice of y. This means we can safely do the following without worrying about division by 0.

\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}

so that

\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23

Similarly,

\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}

so that

\log_da=\dfrac{-\frac23}{\frac89}=-\dfrac34

So we end up with

\log_dabc=-\dfrac34-\dfrac23+\dfrac12=-\dfrac{11}{12}

###

Another way to do this:

\log_ab=\dfrac89\implies a^{8/9}=b\implies a=b^{9/8}

\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}

\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12

Then

abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}

So we have

\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

4 0
3 years ago
Help I don’t understand this ‍♀️
irina [24]
Hello there!
Point A is (-4,2)
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Point C is (-2,-4)
Point D is (-3,1)
Point E is (0,-2)
6 0
3 years ago
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Which of the following equations can be used to find the length of BC in the
ycow [4]

Answer:

BC² = 10² + 30²

the answer is D

4 0
3 years ago
The table below shows the average yearly balance in a savings account where interest is compounded annually. no money is deposit
djverab [1.8K]
A. Linear with a negative rate of change
6 0
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