PLZ HELP URGENT

At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric

Zanzabum

Answer:

a) (1215, 1297)

b) (1174, 1338)

c) (1133, 1379)

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

Also known as 68-95-99.7 rule.
It states that almost all the data lies within three standard deviation for a normal data.
About 68% of data lies within 1 standard deviation of mean.
About 95% of data lies within two standard deviation of mean.
About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

$\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)$

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

$\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)$

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

$\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)$

All of data will be found between 1133 years and 1379 years.

3 0

4 years ago

If m 2 BOC = 27 and m ZAOC = 61, what is the measure of ZAOB?

ivanzaharov [21]

The correct answer is D.

3 0

3 years ago

Directions:Use the product rule to simplify the following monomials.

abruzzese [7]

7) Answer = $-24x^8y^{11}$

$\left(8x^4y^2\right)\left(-3x^4y^9\right)$

$=-8x^4y^2\cdot \:3x^4y^9$

$=-24x^4y^2x^4y^9$

$=-24x^8y^2y^9$

$=-24x^8y^{11}$

8) Answer = $-30y^6$

$2y\left(-5\right)y^2\cdot \:3y^3$

$=-30yy^2y^3$

$=-30y^{1+2+3}$

$=-30y^6$

9) Answer = $-6x^4y^5$

$\left(-2xy\right)\left(xy\right)\left(3x^2y^3\right)$

$=-2xyxy\cdot \:3x^2y^3$

$=-6xyxyx^2y^3$

$=-6x^4yyy^3$

$=-6x^4y^5$

3 0

3 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

wolverine [178]

Answer:

x^4 - 14x^2 - 40x - 75.

Step-by-step explanation:

As complex roots exist in conjugate pairs the other zero is -1 - 2i.

So in factor form we have the polynomial function:

(x - 5)(x + 3)(x - (-1 + 2i))(x - (-1 - 2i)

= (x - 5)(x + 3)( x + 1 - 2i)(x +1 + 2i)

The first 2 factors = x^2 - 2x - 15 and

( x + 1 - 2i)(x +1 + 2i) = x^2 + x + 2ix + x + 1 + 2i - 2ix - 2i - 4 i^2

= x^2 + 2x + 1 + 4

= x^2 + 2x + 5.

So in standard form we have:

(x^2 - 2x - 15 )(x^2 + 2x + 5)

= x^4 + 2x^3 + 5x^2 - 2x^3 - 4x^2 - 10x - 15x^2 - 30x - 75

= x^4 - 14x^2 - 40x - 75.

7 0

4 years ago

Can anyone help with these maths questions about transformations please?

salantis [7]

A. Reflection over y = 2

B. Reflection over y axis, reflection over y = 1

C. I'm guessing you just have to draw this one, just put the center on (2,0) and enlarge it by the scale factor

8 0

3 years ago