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Vilka [71]
3 years ago
11

I don't understand this. Please help!:::: Provide an answer for a, b, c, and d.

Mathematics
1 answer:
OleMash [197]3 years ago
8 0
Answer for part A is  \angle A \cong \angle D which in English means "angle A is congruent to angle D"

The reason why we know that angle A and angle D are congruent is because they are both right angles. By the right angle congruence theorem (the reason just below the blank for part A), we can say that angle A = angle D. They are both 90 degree angles. 

------------------------------------------------
Answer for the blank in part B is "Given" without quotation marks of course. This is the first "given" while the second given is coming up in part C

------------------------------------------------
For part C, the other given is \angle C \cong \angle F so that's what will go in the blank. It may seem silly, but all we're doing is repeating verbatim what is given to us. With any proof, you always start with what you are given and somehow connect it with what you're trying to prove

------------------------------------------------
Finally, the answer for the blank in part D is "AAS Congruence Theorem" (without quotes)

The AAS congruence theorem allows us to prove two triangles congruent if we know if two pairs of angles are congruent plus if we know two sides are congruent as well.

The angle portions are covered by part A and part C. The side portions are part B's territory. Combining A, B, & C allows us to use the AAS theorem

Note: It is NOT the ASA theorem because the two angles do not sandwich the sides. In other words, the side AB is not between the two angles A and C. Similarly, DE is not between the two angles D and F. The order is very important as ASA is slightly different than AAS. 

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joja [24]

Answer:

(5, 4) is correct.

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Then comes y, which is vertical.

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2 years ago
G use part 1 of the fundamental theorem of calculus to find the derivative of the function. sqrt(4+7t)
uysha [10]
Let y = √4+7t
then u= 4+7t
y=√u = u^½

du/dt= 7
dy/du = ½U^-½

dy/dt = du/dt • dy/du
= 7×½U^-½
= 7/2√U
= 7 / (2{√4+7t})
6 0
3 years ago
Help me please. I really need it​
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

can you post a better pic please

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3 years ago
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PLEASE HELP ASAP
White raven [17]

Answer:

(A) It should choose High school Z for the most consistent attendance among its students.

(B) It should choose High school W with the highest average attendance.

Step-by-step explanation:

We are given the data for attendance in the table below, where Low represents the fewest days attended and High represents the most days attended for a single student.

<u>School</u>         Hight School W      High School X       High School Z

Low                       108                          112                          130

High                      180                          180                         180

Range                    72                           68                           50

Mean                    169                          160                          162

Median                 150                          124                          151

IQR                       47.5                         49.5                        39.5

S.D. (σ)                 29.5                         32.4                        27.5

(A) It is stated that the school district wants to award the school that has the most consistent attendance among its students.

Now, to check which high school should it choose; we will look for the standard deviation (σ) of each of the three schools because consistency is measured through standard deviation and the school with the lowest standard deviation means that it has the most consistent attendance among its students.

So, after looking at the standard deviation of all the three schools; the High School Z has the lowest standard deviation of 27.5.

This means that it should choose High school Z.

(B) It is stated that the school district wants to award the school with the highest average attendance.

Now, to check which high school should it choose; we will look for the Mean of each of the three schools because average is measured through mean of the data, and the school with the highest mean means that it has the highest average attendance.

So, after looking at the Mean of all the three schools; the High School W has the highest average of 169.

This means that it should choose High school W with the highest average attendance.

4 0
3 years ago
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Lina20 [59]

Answer:

on what jsoshshsisshsushshdu?

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3 years ago
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