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Lynna [10]
3 years ago
14

What is the distance between the points (4,3) and (1,-1) on the coordinate plane

Mathematics
2 answers:
spayn [35]3 years ago
8 0

Answer:

5 units

Step-by-step explanation:

All that you have to do is use the pythagorean theorem. You can tell that the distance on the x-axis is 3 and on the y-axis is 4, just by subtracting (1,-1) from (4, 3). Then, square the sides, add them, and find the square root of the answer.

4x4 = 16

3x3 = 9

16 + 9 = 25

The square root of 25 is 5. Your answer is 5.

Mariulka [41]3 years ago
7 0

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points (4, 3) and (1, -1). Substitute:

d=\sqrt{(1-4)^2+(-1-3)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

<h3>Answer: The distance between the points (4, 3) and (1, -1) is equal 5 units.</h3>
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3 years ago
What is the measure of B (2n + 15) and D (3n - 5)? If ABCD is a parrallelogram
katovenus [111]

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Step-by-step explanation :

As we know that the opposite angles are equal in parallelogram.

According to the given figure,

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<u>Q</u><u>uest</u><u>ion</u><u>:</u>

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↠1062

▬▬▬▬▬▬▬▬▬▬▬▬

The upper Solution is done by applying BODMAS

<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>

B→ Bracket

O→ Of

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