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3 years ago

What is the distance between the points (4,3) and (1,-1) on the coordinate plane

Mathematics

2 answers:

spayn [35]3 years ago

8 0

Answer:

5 units

Step-by-step explanation:

All that you have to do is use the pythagorean theorem. You can tell that the distance on the x-axis is 3 and on the y-axis is 4, just by subtracting (1,-1) from (4, 3). Then, square the sides, add them, and find the square root of the answer.

4x4 = 16

3x3 = 9

16 + 9 = 25

The square root of 25 is 5. Your answer is 5.

Mariulka [41]3 years ago

7 0

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (4, 3) and (1, -1). Substitute:

$d=\sqrt{(1-4)^2+(-1-3)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5$

<h3>Answer: The distance between the points (4, 3) and (1, -1) is equal 5 units.</h3>

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