1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vlad [161]
3 years ago
11

Find the value of X.

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

As the complete angle is right angle that is 90°

So both the angles should add up to 90°

(3x+2) + (x+16)=90

combine the like terms

4x+18 = 90

Subtract 18 from both sides

4x= 72

divide both sides by 4

x=18

You might be interested in
Use Gaussian Elimination to find an equation of a polynomial that passes through points A(-5,-3), B(-2,3). C(3,3), D(6,19). Indi
Marrrta [24]

Answer:

The polynomial equation that passes through the points is 2-\frac{2}{3}x+\frac{1}{12}x^{2}+\frac{1}{12}x^{3}

Step-by-step explanation:

Suppose you have a function y = f(x) which goes through these points

A(-5,-3), B(-2,3). C(3,3), D(6,19)

there is a polynomial P(x) of degree 3 which goes through these point.

We use the fact that <em>four distinct points will determine a cubic function.</em>

P(x) is the degree 3 polynomial through the 4 points, a standard way to write it is

P(x) = a+bx+cx^2+dx^3

Next replace the given points one by one, which leads to a system of 4 equations and 4 variables (namely a,b,c,d)

-3=a+b\cdot-5+c\cdot -5^2+d\cdot -5^3\\3=a+b\cdot-2+c\cdot -2^2+d\cdot -2^3\\3=a+b\cdot 3+c\cdot 3^2+d\cdot 3^3\\19=a+b\cdot 6+c\cdot 6^2+d\cdot 6^3

We can rewrite this system as follows:

-3=a-5\cdot b+25\cdot c-125\cdot d\\3=a-2\cdot b+4\cdot c-8\cdot d\\3=a+3\cdot b+9\cdot c+27\cdot d\\19=a+6\cdot b+36\cdot c+216\cdot d

To use the Gaussian Elimination we need to express the system of linear equations in matrix form (<em>the matrix equation Ax=b</em>).

The coefficient matrix (A) for the above system is

\left[\begin{array}{cccc}1&-5&25&-125\\1&-2&4&-8\\1&3&9&27\\1&6&36&216\end{array}\right]

the variable matrix (x) is

\left[\begin{array}{c}a&b&c&d\end{array}\right]

and the constant matrix (b) is

\left[\begin{array}{c}-3&3&3&19\end{array}\right]

We also need the augmented matrix, it is obtained by appending the columns of the coefficient matrix and the constant matrix.

\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\1&-2&4&-8&3\\1&3&9&27&3\\1&6&36&216&19\end{array}\right]

To transform the augmented matrix to the reduced row echelon form we need to follow these steps:

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\0&3&-21&117&6\\1&3&9&27&3\\1&6&36&216&19\end{array}\right]

  • Subtract row 1 from row 3 \left(R_3=R_3-R_1\right)

\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\0&3&-21&117&6\\0&8&-16&152&6\\1&6&36&216&19\end{array}\right]

  • Subtract row 1 from row 4 \left(R_4=R_4-R_1\right)

\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\0&3&-21&117&6\\0&8&-16&152&6\\0&11&11&341&22\end{array}\right]

  • Divide row 2 by 3 \left(R_2=\frac{R_2}{3}\right)

\left[\begin{array}{cccc|c}1&-5&25&-125&-3\\0&1&-7&39&2\\0&8&-16&152&6\\0&11&11&341&22\end{array}\right]

  • Add row 2 multiplied by 5 to row 1 \left(R_1=R_1+\left(5\right)R_2\right)

\left[\begin{array}{cccc|c}1&0&-10&-70&7\\0&1&-7&39&2\\0&8&-16&152&6\\0&11&11&341&22\end{array}\right]

  • Subtract row 2 multiplied by 8 from row 3 \left(R_3=R_3-\left(8\right)R_2\right)

\left[\begin{array}{cccc|c}1&0&-10&-70&7\\0&1&-7&39&2\\0&0&40&-160&-10\\0&11&11&341&22\end{array}\right]

  • Subtract row 2 multiplied by 11 from row 4 \left(R_4=R_4-\left(11\right)R_2\right)

\left[\begin{array}{cccc|c}1&0&-10&-70&7\\0&1&-7&39&2\\0&0&40&-160&-10\\0&0&88&-88&0\end{array}\right]

  • Divide row 3 by 40 \left(R_3=\frac{R_3}{40}\right)

\left[\begin{array}{cccc|c}1&0&-10&-70&7\\0&1&-7&39&2\\0&0&1&-4&-1/4\\0&0&88&-88&0\end{array}\right]

  • Add row 3 multiplied by 10 to row 1 \left(R_1=R_1+\left(10\right)R_3\right)

\left[\begin{array}{cccc|c}1&0&0&30&9/2\\0&1&-7&39&2\\0&0&1&-4&-1/4\\0&0&88&-88&0\end{array}\right]

  • Add row 3 multiplied by 7 to row 2 \left(R_2=R_2+\left(7\right)R_3\right)

\left[\begin{array}{cccc|c}1&0&0&30&9/2\\0&1&0&11&1/4\\0&0&1&-4&-1/4\\0&0&88&-88&0\end{array}\right]

  • Subtract row 3 multiplied by 88 from row 4 \left(R_4=R_4-\left(88\right)R_3\right)

\left[\begin{array}{cccc|c}1&0&0&30&9/2\\0&1&0&11&1/4\\0&0&1&-4&-1/4\\0&0&0&264&22\end{array}\right]

  • Divide row 4 by 264 \left(R_4=\frac{R_4}{264}\right)

\left[\begin{array}{cccc|c}1&0&0&30&9/2\\0&1&0&11&1/4\\0&0&1&-4&-1/4\\0&0&0&1&1/12\end{array}\right]

  • Subtract row 4 multiplied by 30 from row 1 \left(R_1=R_1-\left(30\right)R_4\right)

\left[\begin{array}{cccc|c}1&0&0&0&2\\0&1&0&11&1/4\\0&0&1&-4&-1/4\\0&0&0&1&1/12\end{array}\right]

  • Subtract row 4 multiplied by 11 from row 2 \left(R_2=R_2-\left(11\right)R_4\right)

\left[\begin{array}{cccc|c}1&0&0&0&2\\0&1&0&0&-2/3\\0&0&1&-4&-1/4\\0&0&0&1&1/12\end{array}\right]

  • Add row 4 multiplied by 4 to row 3 \left(R_3=R_3+\left(4\right)R_4\right)

\left[\begin{array}{cccc|c}1&0&0&0&2\\0&1&0&0&-2/3\\0&0&1&0&1/12\\0&0&0&1&1/12\end{array}\right]

From the reduced row-echelon form the solutions are:

\left[\begin{array}{c}a=2&b=-2/3&c=1/12&d=1/12\end{array}\right]

The polynomial P(x) is:

2-\frac{2}{3}x+\frac{1}{12}x^{2}+\frac{1}{12}x^{3}

We can check our solution plotting the polynomial and checking that it passes through the points.

3 0
3 years ago
ABC is dilated by a factor of 1/2 to produce A'B'C'
Anton [14]

Answer:

B

Step-by-step explanation:

34 x 1/2 = 17 (Line A'B')

28 x 1/2 = 14 (Angle A')

5 0
3 years ago
Read 2 more answers
Use the grid to create a model to solve the percent problem. 12 is 60% of what number? Enter your answer in the box
Elenna [48]
Is means equal to and of means multiply. So....your equation would be 12=60%x. Now since u can't multiply by a percent, u gotta do 12=.6x. Now divide by .6 so that it cancels out. Your answer is 20. Hope this helps!
3 0
3 years ago
Read 2 more answers
Help me out pls!!!!!!
klio [65]
It is at (2,4) hope it helps
4 0
2 years ago
Read 2 more answers
To rent a certain meeting room, a college charges a reservation fee of $49 and an additional fee of $7.80 per hour. the math clu
yulyashka [42]
The math club could rent the room for up to 8 hours. I have also attached a picture of the work in case you need it.

4 0
3 years ago
Read 2 more answers
Other questions:
  • Factorize completely:<br> 5 - 45/a^2
    8·1 answer
  • The formula I = prt gives the simple interest / earned on an account where an amount p is deposited at an interest rate r for a
    6·1 answer
  • Determine which pizza is the better buy in each situation. The 10-inch diameter pizza for $8.99 or the 6-inch diameter pizza for
    8·2 answers
  • According to the key of a particular park map, every 5 inches on the map represents 3 miles of trails in the park. how many inch
    13·2 answers
  • Can you make an equilateral right triangle
    5·1 answer
  • What is the prime factorization for 160 using exponents?
    15·2 answers
  • 4h-2h+5=19 Solve for h
    10·2 answers
  • Name the subsets of the real number square root 34
    7·1 answer
  • C
    15·1 answer
  • What is m D?<br> mZD =<br> PLZZZ help
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!