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Wewaii [24]
3 years ago
6

Please answer this percent yield question.

Chemistry
1 answer:
Sveta_85 [38]3 years ago
5 0

Answer:

Percent yield = 82.5

Explanation:

Given data:

Actual yield of N₂ = 275 L

Theoretical yield = 333 L

Percent yield = ?

Solution:

Chemical equation:

4HCl + 6NO    →     5N₂ + 6H₂O

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = (275 L/ 333 L ) × 100

Percent yield = 0.825× 100

Percent yield = 82.5%

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What is the density of an object having a mass of 16 g and a volume of 30 mL ?
Marizza181 [45]

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12

Explanation:

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If an object has a Mass of 11g and a volume fo 13mil, what is its density?
Nimfa-mama [501]

Answer:

\boxed {\boxed {\sf B. \ d \approx 0.85 \ g/mL}}

Explanation:

Density is found by dividing the mass by the volume.

d=\frac{m}{v}

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m= 11 \ g \\v= 13 \ mL

Substitute the values into the formula.

d= \frac{11 \ g}{13 \ mL}

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d=0.846153846 \ g/mL

Round to the nearest hundredth. The 6 in the thousandth place tells us to round the 4 to a 5.

d \approx 0.85 \ g/mL

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3 years ago
Which statement best describes the structure of covalent network solids? A. They are giant structures held together by weak forc
konstantin123 [22]

Answer: Option (B) is the correct answer.

Explanation:

A covalent compound is a compound formed by sharing of electrons. And, in a covalent network solid atoms are bonded by covalent bonds in a continuous network that is extending throughout the material or solid.

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If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
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2Ca + O2 = 2CaO
First, determine which is the excess reactant
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65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
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4 years ago
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