Question

Calculate how many grams of the first reactant are necessary to completely react with 17.3 g of the second reactant. the reaction being Na2Co3+CuCl2=CuCo3+2NaCl

Answer 1

Taking into account the reaction stoichiometry, 16.611 grams of Na₂CO₃ are necessary to completely react with 17.3 g of CuCl₂.

Reaction stoichiometry

In first place, the balanced reaction is:

Na₂CO₃ + CuCl₂  → CuCO₃ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

• Na₂CO₃: 1 mole
• CuCl₂: 1 mole
• CuCO₃: 1 mole
• NaCl: 2 moles

The molar mass of the compounds is:

• Na₂CO₃: 129 g/mole
• CuCl₂: 134.45 g/mole
• CuCO₃: 123.55 g/mole
• NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

• Na₂CO₃: 1 mole ×129 g/mole= 129 grams
• CuCl₂: 1 mole ×134.45 g/mole= 134.45 grams
• CuCO₃: 1 mole ×123.55 g/mole= 123.55 grams
• NaCl: 2 mole ×58.45 g/mole=116.9 grams

Mass of CuCl₂ required

The following rule of three can be applied: If by reaction stoichiometry 134.35 grams of CuCl₂ react with 129 grams of Na₂CO₃, 17.3 grams of CuCl₂ react with how much mass of Na₂CO₃?

mass of Na₂CO₃= (17.3 grams of CuCl₂× 129 grams of Na₂CO₃)÷ 134.35 grams of CuCl₂

mass of Na₂CO₃= 16.611 grams

Finally, 16.611 grams of Na₂CO₃ is required.

Learn more about the reaction stoichiometry:

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