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BlackZzzverrR [31]
3 years ago
7

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.

Mathematics
1 answer:
ioda3 years ago
3 0

Answer:

A

Step-by-step explanation:

-When the function moves to the right or left to the x axis, the number has to be in "( )"

-If it moves to the right, you SUBTRACT the amount of units

-It it moves to the left, you ADD the amount of units.

So it is asking about moving to the left so it has to be (x+8)^2 and it cant be C or D because there are not "( )"

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Ilean works as a welder and web designer. As a welder, she earns $18 per hour. Last week she worked 푥 hours as a welder and her
trapecia [35]

The expression that represent the total amount Ilean earned last week is 27(18) + 75  

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let y represent the total amount Ilean earned last week for working x hours.

Since she worked for 27 hours and earned $75 to design a web page. Hence:

y = 27(18) + 75

The expression that represent the total amount Ilean earned last week is 27(18) + 75  

Find out more on equation at: brainly.com/question/2972832

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8 0
2 years ago
A given line has the equation 10x + 2y = −2.
worty [1.4K]

The equation is \boxed{ \ y = - 5x + 12 \ or \ y = 12 - 5x} \ }

<h3>Further explanation </h3>

This case asking the end result in the form of a slope-intercept.

<u>Step-1: find out the gradient. </u>

10x + 2y = -2

We isolate the y variable on the left side. Subtract both sides by 10x, we get:

2y = - 10x - 2  

Divide both sides by two

y = -5x -1

The slope-intercept form is \boxed{ \ y = mx + c \ }, with the coefficient m as a gradient. Therefore, the gradient is m = -5.

If you want a shortcut to find a gradient from the standard form, implement this:  

\boxed{ \ ax + by = k \rightarrow m = - \frac{a}{b} \ }

10x + 2y = −2 ⇒ a = 10, b = 2

\boxed{m = - \frac{10}{2} \rightarrow m = -5}

<u>Step-2:</u> the conditions of the two parallel lines

The gradient of parallel lines is the same \boxed{ \ m_1 = m_2 \ }. So \boxed{m_1 = m_2 = -5}.

<u>Final step:</u> figure out the equation, in slope-intercept form, of the parallel line to the given line and passes through the point (0, 12)

We use the point-slope form.

\boxed{ \ \boxed{ \ y - y_1 = m(x - x_1)} \ }

Given that

  • m = -5
  • (x₁, y₁) = (0, 12)  

y - 12 = - 5(x - 0)

y - 12 = - 5x

After adding both sides by 12, the results is \boxed{ \ y = - 5x + 12 \ or \ y = 12 - 5x} \ }

<u>Alternative steps </u>

Substitutes m = -5 and (0, 12) to slope-intercept form \boxed{ \ y = mx + c \ }

12 = -5(0) + c

Constant c is 12 then arrange the slope-intercept form.

Similar results as above, i.e. \boxed{ \ y = - 5x + 12 \ or \ y = 12 - 5x} \ }

<u>Note: </u>

\boxed{Standard \ form: ax + by = c, with \ a > 0}

\boxed{Point-slope \ form: y - y_1 = m(x - x_1)}

\boxed{Slope-intercept \ form: y = mx + k}

<h3>Learn more </h3>
  1. A similar problem brainly.com/question/10704388
  2. Investigate the relationship between two lines brainly.com/question/3238013
  3. Write the line equation from the graph brainly.com/question/2564656

Keywords: given line, the equation, slope-intercept form, standard form, point-slope, gradien, parallel, perpendicular, passes, through the point, constant

7 0
3 years ago
Read 2 more answers
Triangle LMN has L at (1, -1) and M at (2, 3). Triangle L'M'N' has L' at (-1, -1), M' at (3, -2), and N' is at (-3, 0). What are
fgiga [73]

Answer:

The answer is N(0,-3)

3 0
3 years ago
Which of the following would eliminate the variable on the left side of the given equation? 36 - 19w = -6w + 41.  1. add -19w  2
Paladinen [302]
W=5/13 you just eliminate the negative sign
5 0
3 years ago
Help I’m almost out of time
VladimirAG [237]

Answer: First option.

Step-by-step explanation:

You can idenfity in the figure that \angle FCE is formed by two secants that intersect outside of the given circle.

It is important to remember that, by definition:

 Angle\ formed\ by\ two\ Secants=\frac{1}{2}( Difference\ of\ intercepted\ Arcs)

Knowing this, you can set up the following equation:

m\angle FCE=\frac{1}{2}(BD-FE)

Therefore, you must substitute values into the equation and then evaluate, in order to find the measure of the angle \angle FCE.

This is:

m\angle FCE=\frac{1}{2}(112\°-38\°)\\\\m\angle FCE=37\°

6 0
3 years ago
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