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BlackZzzverrR [31]
2 years ago
7

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.

Mathematics
1 answer:
ioda2 years ago
3 0

Answer:

A

Step-by-step explanation:

-When the function moves to the right or left to the x axis, the number has to be in "( )"

-If it moves to the right, you SUBTRACT the amount of units

-It it moves to the left, you ADD the amount of units.

So it is asking about moving to the left so it has to be (x+8)^2 and it cant be C or D because there are not "( )"

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aniked [119]

Answer: 20

Step-by-step explanation:

So what I did was divide the pages by the hours and got 20

but, when it starts with 20 pages an hour you have... 20

7 0
2 years ago
Carly wants to buy 10 litres of
yuradex [85]

Answer:

The correct answer is:

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4 0
3 years ago
At 9:00 pm bob leaves his home and starts walking to the bus stop at a constant speed of 9.3 feet per second. bob's house is 432
klio [65]
a. define variables for the quantities that are changing (be specific).
 We define variables:
 t = time in second
 d = distance traveled
 The variables that are changing are t and d.
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 b. what does it mean to say bob walks at a constant speed of 9.3 feet per second?
 It means that for every second that passes, Bob walks 9.3 feet.

 c. consider the formula d = 4320 - 9.3t i. what does t represent? ii. what does 9.3t represent? iii. what does d represent? 
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 t = represents the time in seconds
 9.3t = represents the distance traveled by Bob
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5 0
2 years ago
What is 3025/10000 in simplest form?
gulaghasi [49]
101/400 or .3025 is your answer
6 0
2 years ago
A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o
vivado [14]

Since \rho=\dfrac mV (density = mass/volume), we can get the mass/weight of the liquid by integrating the density \rho(x,y,z) over the interior of the tank. This is done with the integral

\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx

which is more readily computed in cylindrical coordinates as

\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}

7 0
3 years ago
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