All categories

3 years ago

A point is on a circle if the distance from the center of the circle to the point is equal to the

Mathematics

1 answer:

solniwko [45]3 years ago

3 0

A) radius: is a line segment that connects the center of a circle to the circumference of a circle or sphere (think perimeter).

You might be interested in

Evaluate this expression: 12 x (3 + 2^2)/2 - 10

BlackZzzverrR [31]

On evaluating the solution is 32

Step-by-step explanation:

Step 1: Use the PEMDAS principle to solve the expression.

⇒ 12 (3 + 2²)/2 - 10 = 12 (3 + 4)/2 - 10

= 12 × 7/2 - 10

= 84/2 - 10

= 42 - 10 = 32

7 0

3 years ago

Read 2 more answers

I need help and ill give brainliest

elena-s [515]

Answer:

(-2,7) reflects to (-2,-7)

(3,9) reflects to (3, -9)

(7,2) reflects to (7,-2)

(-3,9) reflects to (-3,-9)

Step-by-step explanation:

in reflection across the x-axis the x value of the coordinate stays the same and the y value is negated to show it been reflected

7 0

3 years ago

Which equation could be used to find the length of the hypotenuse?

Julli [10]

Answer:

2^2 +5^2 = c^2

Step-by-step explanation:

We can use the Pythagorean theorem to solve for c

a^2 + b^2 =c^2 where a and b are the legs and c is the hypotenuse

2^2 +5^2 = c^2

4+25 = c^2

29 =c^2

3 0

3 years ago

Read 2 more answers

If we list all the natural numbers below 20 that are multiples of 7 or 11, we get 7, 11 and 14. The sum of these multiples is 32

velikii [3]

Number of multiples of 7 up to 1337: $\left\lfloor\dfrac{1337}7\right\rfloor=191$
Number of multiples of 11 up to 1337: $\left\lfloor\dfrac{1337}{11}\right\rfloor=121$
Number of multiples of 77 up to 1337: $\left\lfloor\dfrac{1337}{77}\right\rfloor=17$

This means there are $191+121-17=295$ distinct multiples of 7 *or* 11 up to 1337.

The sum of these multiples is

$\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k$

which can be computed using the well-known formula,

$\displaystyle\sum_{k=1}^nk=\dfrac{n(n+1)}2$

So you have

$\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k=7\dfrac{191\times192}2+11\dfrac{121\times122}2-77\dfrac{17\times18}2=197762$

8 0

3 years ago

What fraction is between 1/2 and1?

skelet666 [1.2K]

3/4 which is 0.75 in decimal

4 0

3 years ago

Read 2 more answers