Recall: SOHCAHTOA
Sin M = Opp/Hyp
Reference angle = M
Opp = 3√/21
Hyp = 15
Sin M = (3-√21)/15
Sin M = √21/5
Cos M = Adj/Hyp
Reference angle = M
Adj = 6
Hyp = 15
Cos M = 6/15
Cos M = 2/5
Tan M = Opp/Adj
Reference angle = M
Opp = 3√21
Adj = 6
Tan M = (3√21)/6
Tan M = √21/2
:Therefore: Sin M = √21/5
Cos M = 2/5
Tan M = √21/2
Answer:
z = 113
y = 31
Step-by-step explanation:
j || n and line a is their transversal. (given)
Therefore,
z° = 180° - 67° (exterior angles on the same side of transversal)
z°= 113°
z = 113
(5y - 88)° = 67° (exterior alternate angles)
5y - 88 = 67
5y = 67 + 88
5y = 155
y = 155/5
y = 31
according to the picture we have:
x.y=4.7
(7)x(7)y=49xy=(49)(4.7)=230.3
Answer:
Step-by-step explanation:
5/7x-4/7x=20-14-4
1/7x=2
x=14
