A x.+ 2 it’s a I got it right on my quiz
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
<h3>Answer: 7 goes in the blank space</h3>
The range of values for x is 2 < x < 7
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Explanation:
The hinge theorem says that the larger the opposite side is, the larger the angle will be.
AD = 11, DC = 8
Since AD > DC, this means angle ABD > angle DBC.
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angle ABD > angle DBC
20 > 4x-8
20+8 > 4x-8+8 ... add 8 to both sides
28 > 4x
4x < 28 ... flip both sides and the inequality sign
4x/4 < 28/4 ... divide both sides by 4
x < 7
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At the same time, the angle 4x-8 cannot be 0 or negative.
So we say 4x-8 > 0. Let's solve this for x.
4x-8 > 0
4x-8+8 > 0+8 ... add 8 to both sides
4x > 8
4x/4 > 8/4 ... divide both sides by 4
x > 2
2 < x ... flip both sides and the inequality sign
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We have 2 < x and x < 7. Both of these combine to the compound inequality 2 < x < 7
We can pick any value between 2 and 7 as long as we dont pick x = 2 or we dont pick x = 7.
Answer:
14.76 cm
Step-by-step explanation:
Use the pythagorean theorem:
a² + b² = c²
Plug in the side lengths and solve for c:
7² + 13² = c²
49 + 169 = c²
218 = c²
14.76 = c
So, the hypotenuse is approximately 14.76 cm
