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Hoochie [10]
3 years ago
13

Which is the equation of a line that has a slope of -2/3 and passes through point (-3,-1)

Mathematics
2 answers:
Eduardwww [97]3 years ago
8 0

Answer:

y = -2/3 x - 3

Step-by-step explanation:

since you have a point and a slope, you can use point - slope form

<h3>y - y_{1} = m (x - x_{1} )   plug in the point as (x_{1}, y_{1}) and the slope as m</h3><h3 /><h3>y - (-1) = -2/3(x - (-3))      change two negatives into positive</h3><h3>y + 1 = -2/3 (x+3)            distribute the -2/3</h3><h3>y + 1 = -2/3x - 2              subtract 1 from both sides</h3><h3>y     = -2/3 x -3</h3>
DiKsa [7]3 years ago
5 0

Answer:

y = -2/3x - 3

Step-by-step explanation:

y = mx + b

m = slope

(-3,-1) = (x,y)

<em>Plus in the coordinates</em>

-1 = -2/3(-3) + b

<em>negative times negative = positive</em>

-2/3 * -3 = 2

-1 = 2 +b

<em>Use inverse operations</em>

-2 --2

-3 = b

y = -2/3x - 3

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