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Hoochie [10]
3 years ago
13

Which is the equation of a line that has a slope of -2/3 and passes through point (-3,-1)

Mathematics
2 answers:
Eduardwww [97]3 years ago
8 0

Answer:

y = -2/3 x - 3

Step-by-step explanation:

since you have a point and a slope, you can use point - slope form

<h3>y - y_{1} = m (x - x_{1} )   plug in the point as (x_{1}, y_{1}) and the slope as m</h3><h3 /><h3>y - (-1) = -2/3(x - (-3))      change two negatives into positive</h3><h3>y + 1 = -2/3 (x+3)            distribute the -2/3</h3><h3>y + 1 = -2/3x - 2              subtract 1 from both sides</h3><h3>y     = -2/3 x -3</h3>
DiKsa [7]3 years ago
5 0

Answer:

y = -2/3x - 3

Step-by-step explanation:

y = mx + b

m = slope

(-3,-1) = (x,y)

<em>Plus in the coordinates</em>

-1 = -2/3(-3) + b

<em>negative times negative = positive</em>

-2/3 * -3 = 2

-1 = 2 +b

<em>Use inverse operations</em>

-2 --2

-3 = b

y = -2/3x - 3

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 In this pattern, we added 3,5,7 and 9 respectively to the previous number. In this way, to get the next numbers, we need to add 11,13,15,17 and 19 respectively to get the answer to previous number.
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Answer:

Step-by-step explanation:

\text{The data given for the quality measurement and other criteria can be seen below:}

Quality management      Excellent      Good      Fair      Total

Excellent                             40                   25         5             70

Good                                   35                    35        10            80

Fair                                       25                   10         15             50

Total                                    100                   70        30           200

The null and alternative hypothesis:

\mathbf{H_o: \text{the quality management and reputation are independent} }

\mathbf{H_a: \text{the quality management and reputation are not independent} }

The expected value is calculated by using the formula:

E=\dfrac{row  \ total \times column  \ total }{table \  total}

After using the formula to calculate the table above; we have:

The expected values of the data to be:

Quality management     Excellent         Good      Fair      Total

Excellent                            35                  24.5       10.5      70

Good                                  40                   28         1.2         80

Fair                                     25                  17.5        7.5         50

Total                                   100                  70        30           200

Degree of freedom = ( row - 1 ) × ( column -1 )

= (3 - 1 ) \times (3 -1)

= 2\times 2

=4

\text{The p-value at level of significance of 0.05 and degree of freedom of 4 =  }\mathbf{0.0019}

Decision rule: To reject the \mathbf{H_o} if the p-value is less than the ∝

Conclusion: We reject the \mathbf{H_o} and conclude that quality management and reputation are not independent.

(B)\text{The P-value here implies that in case that there is no dependence between the two ratings, }\text{the probability that they will seem to show at least this kind of strong dependence is 0.0019.}

\text{Thus, the probability that they will seem to show at least this kind of strong independence is =}\mathbf{0.0019}

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