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Keith_Richards [23]
2 years ago
12

The point P = (-3, y) lies on the unit circle shown below. What is the value of y

Mathematics
1 answer:
alukav5142 [94]2 years ago
5 0

The equation of the circle is given as (x-h)² + (y-k)² = r². Then the value of y will be ± √5/3.

<h3>What is an equation of a circle?</h3>

A circle can be characterized by its center's location and its radius's length.

Let the center of the considered circle be at (h, k) coordinate.

Let the radius of the circle be 'r' units.

Then, the equation of that circle would be:

(x-h)² + (y-k)² = r²

The equation of the circle has the center at the origin and the radius is one unit. Then we have

x² + y² = 1

The point P = (-2/3, y) lies on the unit circle. Then the value of y will be

(-2/3)² + y² = 1

y² = 1 - 4/9

y² = 5/9

y = ± √5 / 9

Learn more about the equation of a circle here:

brainly.com/question/10165274

#SPJ1

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Answer:

perimeter = 20.9 units

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perimeter = distance around two dimensional shape

= addition of all sides lengths

<h2>perimeter of the figure</h2><h2>= AB+BC+CD+AD</h2>

distance formula:

d =  \sqrt{(  x_{2} -  x_{1})  {}^{2}   + ( y_{2} -  y_{1}) {}^{2}  }

<h3>1) distance of AB</h3>

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(substitute the values into the distance formula)

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<h3>2) distance of BC</h3>

B(2,4) C(3,1)

x1 = 2 x2 = 3

y1 = 4 y2 = 1

bc =  \sqrt{(3 - 2) {}^{2}  + (1 - 4) {}^{2} }

bc = \sqrt{1 {}^{2} + ( - 3) {}^{2}  }

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<h3>3) distance of CD</h3>

C(3,1) D(-4,-3)

x1 = 3 x2 = -4

y1 = 1 y2 = -3

cd =  \sqrt{( - 4 - 3) {}^{2}  + ( - 3 - 1)) {}^{2} }

cd =  \sqrt{( -   7) {}^{2}  + ( - 4 ){}^{2} }

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<h3>4) distance of AD</h3>

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

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AD = 3.2 units

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= AB+BC+CD+AD

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