Answer:
<u>-5 ± √5² - 4 · 1 · 4</u>
2 · 1
Step-by-step explanation:
ax²+bx+c=0 (quadratic equation)
x=<u> -b ± √b² - 4ac</u>
2a
a= 1
b= 5
c= 4
-<u>5 ± √5² - 4 · 1 · 4</u>
2 · 1
2^3:
a) 2 x 2 x 2
b) 8
3^2 x e^3:
a) 3 x 3 x e x e x e
b) 9e^3
Answer: If the plane descends at the rate of 0.2 km per minute and landed after 15 mins, that means the plane started at 3 km elevation when it started to descend (t=0). The table is then constructed using the intialn values.
We have been given a function . We are asked to find the amplitude, period and phase shift of the function
We can see that our given function is in form , where,
= Amplitude.
Period =
C = Horizontal shift,
D = Vertical shift.
We can see that value of a is 1, therefore, the amplitude of given function would be 1.
We can see that B is equal to 8, so we will get:
Therefore, the period of given function is .
Since the value of C is 1, therefore, horizontal shift is 1.
Since the value of D is 2, therefore, vertical shift would be 2.