"Sulfur, a nonmetal with 6 valence electrons"
For light or ultraviolet, the formula for energy can be
calculated using Planck’s equation. That is:
E = h c / ʎ
where,
h is the Planck’s constant = 6.626 * 10^-34 m^2 kg
/ s
c is the speed of light = 3 * 10^8 m/s
ʎ is the wavelength of light = 110 nm = 110 x 10^-9 m
So calculating for energy E:
E = (6.626 * 10^-34 m^2 kg / s) * (3 * 10^8 m/s) /
(110 x 10^-9 m)
E = 1.807 x 10^-18 J
Q = C.v
v = Q/C
v = 4 × 10^(-10)/250
= 4 × 10^(-10)/2.5 × 10^2
= 1.6 × 10^(-12) volt
This is a conservation of momentum problem! Here's how to do it:
Answer:
real, inverted, and smaller than the object
Explanation:
When the object is placed beyond the center of curvature, the image will formed between the focus and the center of curvature. The size of the image is diminished and its nature is real and inverted.
The whole description is shown in the attached figure. It is clear that the size of the image is smaller than the object.
