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IrinaK [193]
3 years ago
10

If electric lights are an accurate gauge of electricity usage, what areas use the most electricity?

Physics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

Places like cities

Explanation:

Cities have more necessities when it comes to technology like live TV, technology companies, electric companies, homes in cities for things like the TV, AC, more luxurious stuff, and I can't even list more because there are so many technological reasons they use, well, technology.

It all comes down to logic and thinking.

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--  Coal
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3 years ago
If you double the diameter of a telescope, you double its light-collecting area.
Ahat [919]

Answer:true

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2 years ago
A cylindrical specimen of some metal alloy 11.2 mm (0.4409 in.) in diameter is stressed elastically in tension. A force of 14100
MrRissso [65]

Answer:

μ = 0.436

Explanation:

Given:

Change in diameter, ΔD = 7 × 10⁻³ mm

Original diameter, D = 11.2 mm = 11.2 × 10⁻³ m

Applied force, P = 14100 N

Cross-section area of the specimen, A = \frac{\pi}{4}D^2 =  \frac{\pi}{4}(11.2\times 10^{-3})^2

Now,

elongation due to tensile force is given as:

\delta = \frac{PL}{AE}

or

\frac{\delta}{L} = \frac{P}{AE}

on substituting the values, we get

\frac{\delta}{L} = \frac{14100}{\frac{\pi}{4}(11.2\times 10^{-3})^2\times100\times 10^9}

or

\frac{\delta}{L} = 0.00143=\epsilon_x

where,

\epsilon_x is the strain in the direction of force

Now,

\epsilon_z=\frac{\Delta D}{D}=\frac{7\times 10^{-3}}{11.2}=0.000625

now, the poisson ratio, μ is given as:

\mu=\frac{\epsilon_z}{\epsilon_x}

on substituting the values we get,

\mu=\frac{0.000625}{0.00143}=0.436

7 0
3 years ago
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Answer:

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A ratio that compares the length and width of a garden is what type of model?
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Answer:

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