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horsena [70]
3 years ago
11

Because of inertia, it will be ____ to stop a larger object than a smaller object if they are both moving at the same speed.

Physics
2 answers:
strojnjashka [21]3 years ago
8 0

Answer:

harder

heavier objects resist change more than lighter objects.

densk [106]3 years ago
3 0
Harder
This is because larger objects have more mass and thus more inertia
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5 0
2 years ago
We drive at a speed of 20 km/h for 3 hours. Then we drive 4 hours at 30 km/h. Calculate our average speed.
Afina-wow [57]

First speed = 20km/h

Time = 3 hours

Distance = 3×20

<h3> = <u>60 km</u></h3>

Second speed = 30km/h

Time = 4 hours

Distance = 4×30

<h3> = <u>120 km</u></h3>

Total distance = 60+120 = <u>180km</u>

Total time = 3+4 =<u> 7 hours</u>

Average speed = 180/7

<h3> = <u>25.71</u><u> </u><u>km</u><u>/</u><u>h</u></h3>

Hope this will help...

4 0
3 years ago
Read 2 more answers
Consider a glider flying at 400 meters altitude, when suddenly all its static ports become blocked by volcanic ash. The pressure
Furkat [3]

Answer:

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

Explanation:

Pitot tube

U = \sqrt{\frac{(p_t - p_s)2}{d} }

U = velocity(m/s)

p_t= stagnation pressure (pa)

p_s= static pressure (pa)

d = fluid density(kg/m³)

p_t = p_a_t_m + \frac{1}{2} dv^2

v = true velocity

= 101325 + 1/2(1.225)(25)²

p_t = 101,707.8125pa

p_s = 96,610pa

d = 1.225kg/m³

U = \sqrt{\frac{2(101,707.8125 - 96,610)}{1.225} } \\\\U = 91.23m/s

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

5 0
3 years ago
A 2 nC point charge is at the origin, and a second 5 nC point charge is on the x-axis at x = 8 m. Find the electric field (magni
dimaraw [331]

Answer:

The magnitude of  the electric field is 5.75 N/C towards positive x- axis.

Explanation:

Given that,

Point charge at origin = 2 nC

Second charge = 5 nC

Distance at x axis = 8 m

We need to calculate the electric field at the point x = 2 m

Using formula of electric field

E=\dfrac{1}{4\pi\epsilon_{0}}(\dfrac{q_{1}}{r_{1}^2}+\dfrac{q_{2}}{r_{2}^2})

Put the value into the formula

E=9\times10^{9}\times(\dfrac{2\times10^{-9}}{2^2}+\dfrac{5\times10^{-9}}{(8-2)^2})

E=5.75\ N/C

The direction is toward positive x- axis.

Hence, The magnitude of  the electric field is 5.75 N/C towards positive x- axis.

7 0
2 years ago
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ioda
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4 0
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