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lubasha [3.4K]
3 years ago
14

When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel 2.5 x 10-15 m before

interacting. From this information, find the time interval required for the strong interaction to occur.
Physics
1 answer:
Tasya [4]3 years ago
8 0

Explanation:

It is given that,

When a high-energy proton or pion traveling near the speed of light collides with a nucleus, d=2.5\times 10^{-15}\ m

Speed of light, c=3\times 10^{8}\ m\s

Let t is the time interval required for the strong interaction to occur. The speed is given by :

c=\dfrac{d}{t}

t=\dfrac{d}{c}

t=\dfrac{2.5\times 10^{-15}\ m}{3\times 10^{8}\ m/s}

t=8.33\times 10^{-24}\ s

So, the time interval required for the strong interaction to occur is 8.33\times 10^{-24}\ s. Hence, this is the required solution.

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Explanation:

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b.

Lets find the distance and recall our third equation of motion.

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Dividing both sides with 2a we have.

\frac{V_{f} ^2-V{i}^2}{2a} = 2as

Plugging the values.

\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as

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So Mr.Comer will travel a distance of s= 18.75\ m.

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