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Airida [17]
2 years ago
12

Im du.mb at this stuff, i dont know how to do it

Mathematics
2 answers:
Anon25 [30]2 years ago
8 0

Answer:

the correct answer will be 88

sp2606 [1]2 years ago
6 0

Answer:

Area of the shaded region 45.76 cm².

Step-by-step explanation:

Firstly, finding the area of rectangle by substituting the values in the formula :

{\longrightarrow{\pmb{\sf{A_{(Rectangle)} = l \times b}}}}

  • → A = Area
  • → l = length
  • → b = breadth

\begin{gathered} \qquad{\longrightarrow{\sf{A_{(Rectangle)} = l \times b}}}\\\\\qquad{\longrightarrow{\sf{A_{(Rectangle)} = 12\times 8}}}\\\\\qquad{\longrightarrow{\sf{A_{(Rectangle)} = 96}}}\\\\\qquad{\star{\boxed{\sf{\pink{A_{(Rectangle)} = 96 \:  {cm}^{2}}}}}} \end{gathered}

Hence, the area of rectangle is 96 cm².

\rule{200}2

Secondly, finding the area of circle by substituting the values in the formula :

{\longrightarrow{\pmb{\sf{A_{(Circle)} =  \pi{r}^{2}}}}}

  • → A = Area
  • → π = 3.14
  • → r = radius

\begin{gathered} \qquad{\longrightarrow{\sf{A_{(Circle)} =  \pi{r}^{2}}}} \\  \\ \qquad{\longrightarrow{\sf{A_{(Circle)} = 3.14{(4)}^{2}}}} \\  \\ \qquad{\longrightarrow{\sf{A_{(Circle)} = 3.14{(4\times 4)}}}} \\  \\ \qquad{\longrightarrow{\sf{A_{(Circle)} = 3.14(16)}}} \\  \\ \qquad{\longrightarrow{\sf{A_{(Circle)} = 3.14 \times 16}}} \\  \\ \qquad{\longrightarrow{\sf{A_{(Circle)}  \approx 50.24}}} \\  \\ \qquad{\star{\boxed{\sf{\purple{A_{(Circle)} \approx 50.24 \: {cm}^{2}}}}}} \end{gathered}

Hence, the area of circle is 50.24 cm².

\rule{200}2

Now, finding the area of shaded region by substituting the values in the formula :

\longrightarrow{\pmb{\sf{A_{(Shaded)} = A_{(Rectangle)} -  A_{(Circle)}}}}

  • → A = Area
  • → Rectangle
  • → Circle

\begin{gathered}{\quad{\longrightarrow{\sf{A_{(Shaded)} = A_{(Rectangle)} -  A_{(Circle)}}}}}\\\\{\quad{\longrightarrow{\sf{A_{(Shaded)} = 96 - 50.24}}}}\\\\{\quad{\longrightarrow{\sf{A_{(Shaded)} \approx 45.76}}}}\\\\{\quad{\star{\boxed{\sf{\red{A_{(Shaded)} \approx 45.76 \:  {cm}^{2}}}}}}} \end{gathered}

Hence, the area of shaded region is 45.76 cm².

\rule{300}{2.5}

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