The two linear equations represented in system A as :
3 x + 2 y =3 -------(1)
- 2 x - 8 y = -1 ------(2)
(1) × 2 + (2) × 3 gives
⇒ 6 x + 4 y - 6 x - 24 y = 6 -3
⇒ - 20 y = 3
⇒ y = 
Putting the value of y in equation (1), we get

Two linear equation represented in system B is:
3. -x - 14 y =1
4. - 2 x - 8 y = -1
-2 ×Equation (3) + Equation (4)=
2 x +28 y- 2 x - 8 y= -2 -1
⇒ 20 y = -3
⇒y =
Putting the value of y in equation (3),we get

As Two system , that is system (A) and System (B) has same solution.
By looking at all the options , i found that Option (D) is correct. The two system will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 2 times the second equation of System A.
Answer:
1) y = 2(x+3)^2 -4
2) x+6/x-4
3) 2x^2 + 6x +20 = 0
Step-by-step explanation:
Answer:
8cx + 12c
Step-by-step explanation:
Multiply the parentheses by 4 and then calculate the products
Answer:
A math test
Step-by-step explanation:
The factory made 3 batches of cookies.
(See my work below)