Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.
Step-by-step explanation: As it is stipulated, <u>x</u> relates to type-A and y to type-B.
Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:
60x + 80y ≤ 360
For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:
160x + 120y ≤ 680
To calculate how many of each type you need:
60x + 80y ≤ 360
160x + 120y ≤ 680
Isolating x from the first equation:
x = 
Substituing x into the second equation:
160(
) + 120y = 680
-3200y+1800y = 10200 - 14400
1400y = 4200
y = 3
With y, find x:
x = 
x = 
x = 2
To determine the cost:
cost = 42,000x + 51,000y
cost = 42000.2 + 51000.3
cost = 161400
To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400
This turns out to be a division problem. To find how many each person can get, you must divide the amount of food by how many guests.
126 divided by 21 is 6
84 divided by 21 is 4
Each guest will get 6 chocolate truffles and 4 caramel truffles.
5 3/8 rounds to 5,
4 7/10 rounds to 5
Your estimated sum is 10
Just borrow from the 7 and take the 1 to the 2 and that will make it as 12 so then you subtract 12 - 4 and the answer will be 1,180
To find a slope we have to use this equation:
(y2 - y1 )/(x2 - x1)
and we have two x's and y's
so we will put them in their places....so (1-(-5))/(4-2)
and we will get 6/2 which is 3
Its A.3
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