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svetoff [14.1K]
3 years ago
14

3(2c+d)-4(c-d)+d squared when c=1 d=3 please explain steps

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

3(2c+d)-4(c-d)+d^2.

6c+3d-(4c+4d)+d^2.

6×1+3×3-4×1+4×3+9.

6+9-4+12+9=32.

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Answer:

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Step-by-step explanation:

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Fudgin [204]

Answer:

(x+4)^2+(y+6)^2=100

Step-by-step explanation:

Given a circle centred at the point P(-4,-6) and passing through the point

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\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{Radius=}\sqrt{(2-(-4))^2+(2-(-6))^2} \\=\sqrt{(2+4))^2+(2+6)^2}\\=\sqrt{6^2+8^2}\\=\sqrt{100}\\Radius=10

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The general form of the equation of a circle passing through point (h,k) with a radius of r is given as: (x-h)^2+(y-k)^2=r^2

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Therefore, the equation of the circle is:

(x-(-4))^2+(y-(-6))^2=10^2\\\\(x+4)^2+(y+6)^2=100

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