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horsena [70]
4 years ago
15

Please help...will mark brainlyest for a real answer

Mathematics
1 answer:
Gennadij [26K]4 years ago
5 0

Answer:

26%

Step-by-step explanation:

There are 23 total classmates.  6 of the classmates take music lessons.

To find the percentage of classmates who take music lessons, divide the classmates who take music lessons by the total classmates.

6/23 = 0.26

0.26 = 26%

26% of students take music lessons.

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X2 -5x+6<br> To solve a quadratic equation, start by factoring,
Y_Kistochka [10]

Answer:

x=2 OR x=3

Step-by-step explanation:

Given equation:

x^2 -5x+6=0

Solving the equation for 'x':

Using factorization method:

x^2-2x-3x+6=0

Making the factors by taking common:

x(x-2)-3(x-2)=0\\(x-2)(x-3)=0

x-2=0\\\\x=2

OR

x-3=0\\\\x=3

3 0
3 years ago
Please help! will give brainliest! ​
Lunna [17]

Answer:

i got 1/12 for 5, 12 for 6, and 1/12 for 7. 8 is 3/2, 9 is 4/5, 10 is 4/9, 11 is 2 1/2.

5 0
3 years ago
Given the figure. Find AC.
Angelina_Jolie [31]

Image is missing, so i have attached it.

Answer:

AC = 10sin 40°

Step-by-step explanation:

From the diagram attached, using terms in trigonometric ratio, AC is the opposite side, BC is the adjacent side and AB is the hypotenuse.

Thus, since we want to find AC;

We know that in trigonometric ratios; opposite/hypotenuse = sin θ

In the diagram, θ = 40° and AB = 10

Thus,

AC/10 = sin 40°

Multiply both sides by 10 to get;

AC = 10sin 40°

7 0
4 years ago
Why is it important to graph terms of ordered pairs in the correct order on a coordinate plane
Alexxandr [17]

Step-by-step explanation:

When an ordered pair refers to the location of a point in the coordinate plane, they are called the coordinates of the point. The order is important because a point named by the ordered pair ( 5, 3 ) is not at the same location as the point named by the ordered pair ( 3, 5 ).

8 0
3 years ago
Read 2 more answers
Solve by completing the square​
erastovalidia [21]

Answer:

Your answers would be:

x = 10 and x = -8

Step-by-step explanation:

Solve for the zeros:

x² - 2x - 78 = 2

Subtract both sides by 2.

x² - 2x - 80 = 0

Use the quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 1

b = -2

c = -80

Plug in and solve:

x=\frac{-(-2)\pm\sqrt{(-2)^2-4(1)(-80)}}{2(1)}\\\\x=\frac{2\pm\sqrt{(-2)^2-4(1)(-80)}}{2(1)}\\\\x=\frac{2\pm\sqrt{4-4(-80)}}{2(1)}\\\\x=\frac{2\pm\sqrt{4+320}}{2(1)}\\\\x=\frac{2\pm\sqrt{324}}{2(1)}\\\\x=\frac{2\pm18}{2}\\

Solve for +:

x=\frac{2+18}{2}\\\\x=\frac{20}{2}\\\\x=10

Solve for -:

x=\frac{2-18}{2}\\\\x=\frac{-16}{2}\\\\x=-8

5 0
3 years ago
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