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4 years ago

Given the figure. Find AC.

Mathematics

1 answer:

Angelina_Jolie [31]4 years ago

7 0

Image is missing, so i have attached it.

Answer:

AC = 10sin 40°

Step-by-step explanation:

From the diagram attached, using terms in trigonometric ratio, AC is the opposite side, BC is the adjacent side and AB is the hypotenuse.

Thus, since we want to find AC;

We know that in trigonometric ratios; opposite/hypotenuse = sin θ

In the diagram, θ = 40° and AB = 10

Thus,

AC/10 = sin 40°

Multiply both sides by 10 to get;

AC = 10sin 40°

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find the distance between -3/4 and 1 3/4 on a number line. write your answer as a fraction or mixed number in simplest form.

Sonja [21]

Answer:

My Guess: 1

Step-by-step explanation:

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4 years ago

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2 years ago

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What is the area of this rectangle?

Rufina [12.5K]

Answer:

The answer to your question is: 40u²

Step-by-step explanation:

Data

Find the vertex

A (-4, 0)

B (-6, 4)

C (2, 8)

D (4, 4)

Formula

d = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }$

Area = base x height

Process

1.- Find the distance from A to B, and the distance from A to D

2.- Obtan the area of the rectangle

1.-

dAB = $\sqrt{(-6 + 4)^{2} + (4 - 0)^{2} }$

dAB = $\sqrt{2^{2} + 4^{2} }$

dAB = $\sqrt{4 + 16}$

dAB = $\sqrt{20}$

dAD = $\sqrt{(4 + 4)^{2} + (4 - 0)^{2} }$

dAD = $\sqrt{8^{2} + 4^{2} }$

dAD = $\sqrt{64 + 16}$

dAD = $\sqrt{80}$

2.-

Area = $\sqrt{20} x \sqrt{80}$

Area = $\sqrt{20x80}$

Area = $\sqrt{1600}$

Area = 40u²

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3 years ago