Answer:
a) Depth changing rate of change is 
, When the water is 6 meters deep
b) The width of the top of the water is changing at a rate of 
, When the water is 6 meters deep
Step-by-step explanation:
As we can see in the attachment part II, there are similar triangles, so we have the following relation between them 
, then 
.
a) As we have that volume is 
, then 
, so we can derivate it 
due to the chain rule, then we clean this expression for 
and compute with the knowns 
, is the depth changing rate of change when the water is 6 meters deep.
b) As the width of the top is 
, we can derivate it and obtain 
The width of the top of the water is changing, When the water is 6 meters deep at this rate
Subtract two from your get 2
In order to solve this problem, you must draw a right triangle first to help you visualize the path of the jogger.
You are given 0.5 miles north (which will be the height of the right triangle), and 1.3 miles (which will be the hypotenuse of the triangle).
Using Pythagorean Theorem: a²+b²=c², we have:
0.5² + b² = 1.3²
b = 1.3²-0.5²
b = 1.2 miles
Ya what the person above me said
