A number that is less that 7.5 can be used as the lesser of the two consecutive integers with the sum greater than 16, but only if the number used was added with one.
we have that
x + 3y = 6 -------> first equation
2x − y = 10
x + 3y = 6-----> substract x both sides
-x+x+3y=6-x
3y=6-x-----> divide by 3 both sides
y=(6-x) /3
y=2-(x/3)
y=-(x/3)+2
therefore
the answer is
negative one thirdx + 2
I HAVE NO IDEA WHAT THE ANSWER IS!!! CAN YOU TELL ME???
