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2 years ago

What is the area of the semicircle?

Mathematics

1 answer:

Serggg [28]2 years ago

6 0

Step-by-step explanation:

$Area (semi-circle)= \frac{r^2\pi }{2}$

$A = \frac{(11)^2\pi }{2}$

$A=\frac{121\pi }{2}$

$A=\frac{379.94}{2}$

$A=189.97$

The area of the semi-circle is 189.97

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Solve the following system using the SUBSTITUTION method.<br> x - 3y = 2<br> 2x - 6y = 6

notka56 [123]

ANSWER:

x – 3y = 2 ...(1)
2x – 6y = 6 ...(2)

On solving eq(1), we get

x – 2 = 3y
x – 2/3 = y

Plug the value of x in eq(2)

2x – 6(x - 2/3) = 6
2x – 2(x – 2) = 6
2x – 2x + 4 = 6
0 = 6 – 4
0 ≠ 2

So, given system of equations is not correct.

6 0

2 years ago

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Brainliest question please help please help me now plz

Kruka [31]

Answer:

Option A) Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

$d\sqrt{(y2-y1)^2+(x2-x1)^2 }$

we have

A(-5,-8),M(-1,-3)

substitute the values

$r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}$

$r=\sqrt{(5)^{2}+(4)^{2}}$

$r=\sqrt{41}\ units$

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

$d=\sqrt{(2)^{2}+(-6)^{2}}$

$d=\sqrt{40}\ units$

$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

Hope that helped :)

8 0

2 years ago

Is 3x + 2y = 5 direct variation

Elena-2011 [213]

Answer:

What is the constant variation of Y =- 2 3x?

The constant of variation, k , is 23 .

Step-by-step explanation:

When x is zero in a direct variation equation y will also be zero. That means that the y-intercept of all direct variation equations is always zero.

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2 years ago

I don’t know how to do these problems so please help me.

Olin [163]

Answer:

36s^3

Step-by-step explanation:

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2 years ago

Given the following functions f(x) and g(x), solve (f/g)(-4) and select the correct answer below. F(x)=4x-4 G(x)=x-1

yan [13]

To start set up a fraction with the f(x) on top and g(x) on bottom
(f/g)(x) = (4x - 4)/(x - 1) - This is the function that we are going to use

Plug in -4 for x
(f/g)(-4) = (4(-4) - 4)/(-4 - 1) = (-16 - 4)/(-5) = (-20)/(-5) = 4

So...
(f/g)(-4) = 4

4 0

2 years ago

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