Answer:
(a)1/6
(b)1/12
Step-by-step explanation:
Given that the cubes are numbered from 1 to 6.
The possible outcomes are:
(1,1)	(1,2)	(1,3)	(1,4)	(1,5)	(1,6)
(2,1)	(2,2)	(2,3)	(2,4)	(2,5)	(2,6)
(3,1)	(3,2)	(3,3)	(3,4)	(3,5)	(3,6)
(4,1)	(4,2)	(4,3)	(4,4)	(4,5)	(4,6)
(5,1)	(5,2)	(5,3)	(5,4)	(5,5)	(5,6)
(6,1)	(6,2)	(6,3)	(6,4)	(6,5)	(6,6)
Total number of possible Outcomes=36
<u>Part A</u>
Probability that the sum of the number cubes is 7.
The outcomes that sums up to 7 are:
(1,6) (2,5)	(3,4) (4,3) (5,2) (6,1)
Number of outcomes=6
Therefore:
P(sum of the number cubes is 7)=6/36=1/6
<u>Part B</u>
The sum of the number cubes is less than 4.
Outcomes in which the sum is less than 4 are:
(1,1)	(1,2)	(2,1)	
Number of outcomes=3
Therefore:
P(sum of the number cubes is less than 4)=3/36=1/12