We are given the function: <span> 1 divided by the quantity x minus 2 squared and is asked in the problem to determine the limit of x as x approaches 2 as well as vertical asymptotes if there are any. To find the limit, we just have to substitute the equation with the value of the numerical limit. The equation then becomes, 1/ (x-2)^2 = 1/(2-2)^2 = 1/0 . Any number divided by zero is equal to infinity so the limit is infinity. A vertical asymptote is the value of x in which the denominator becomes zero, that is (x-2)^2 = 0; x = 2. The vertical asymptote is equal to 2.</span>
Ok so
for a thing that is P amount at first, with a half life of k days
after t days, the amount left is A
the equation is
given
13% of P remained=A
t=400
replace A with 0.13P and t with 400
0.13P=
divide both sides by P
take the ln of both sides
multiply both sides by k
divide oth sides by ln0.13
k=
evaluate
k=135.897 days
the half life is 135.897 days
Answer:
N=9
Step-by-step explanation:
7n+8=71
7n=71-8
7n=63
N=63/7
N=9
I think it is 5/6 because you would have to choose a small amount
Answer:
96π cm²
Step-by-step explanation:
Use the formula for the surface area of a cylinder:
A = 2πrh + 2πr²
Plug in the height and radius, and solve:
A = 2π(4)(8) + 2π(4)²
A = 2π(32) + 2π(16)
A = 64π + 32π
A = 96π
So, the surface area of the cylinder is 96π cm²